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How do you find the total width of the ellipse given by the equation 7x^2 + 7(y-6)^2 = 6?
The total width of the ellipse represented by the equation 7x² + 7(y-6)² = 6 can be determined by converting it into standard form. The standard form of an ellipse is given by (x - x₀)²/a² + (y - y₀)²/b² = 1, where (x₀, y₀) is the center, 'a' is the semi-major axis, and 'b' is the semi-minor axis. By dividing the entire equation by 6, the equation transforms to (x²/6/7) + ((y-6)²/6/7) = 1, revealing that the total width of the ellipse is 2a, which equals 2√(6/7).
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