Finding Total Width of Ellipse in Standard Form

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SUMMARY

The total width of the ellipse represented by the equation 7x² + 7(y-6)² = 6 can be determined by converting it into standard form. The standard form of an ellipse is given by (x - x₀)²/a² + (y - y₀)²/b² = 1, where (x₀, y₀) is the center, 'a' is the semi-major axis, and 'b' is the semi-minor axis. By dividing the entire equation by 6, the equation transforms to (x²/6/7) + ((y-6)²/6/7) = 1, revealing that the total width of the ellipse is 2a, which equals 2√(6/7).

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How do you find the total width of the ellipse given by the equation 7x^2 + 7(y-6)^2 = 6?
 
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The "standard form" for an ellipse is
[tex]\frac{(x- x_0)^2}{a^2}+ \frac{(y- y_0)^2}{b^2}= 1[/tex]
Where [itex](x_0,y_0)[/itex] is the center of the ellipse, a is the distance from the center of the ellipse and points where the ellipse crosses the x-axis and b is the distance from the center of the ellipse to the points where the ellipse crosses the y- axis. First change your equation to that form (Notice the "1" on the right hand side. How do you get that?). What does that tell you about the total width of the ellipse?
 

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