Finding unknown frequency from beats?

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To find the unknown resonant frequency of a tuning fork, the known frequencies of 360 Hz and 358 Hz produce beat frequencies of 2 Hz and 4 Hz, respectively. The relationship between beat frequency and the two fork frequencies indicates that the unknown frequency must be greater than 360 Hz. By analyzing the beat frequencies, it can be determined that the unknown frequency is 362 Hz, as it satisfies both conditions: 2 Hz difference with 360 Hz and 4 Hz difference with 358 Hz. Therefore, the unknown frequency of the tuning fork is confirmed to be 362 Hz.
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Finding unknown frequency from beats?

Homework Statement



i have to find the unknown resonant frequency of a tuning fork??

Homework Equations



when this unknown is struck along a known freq of 360 hertz = you hear beat frequency of 2 hertz.. and when its struck alongside a known freq of 358 = you hear beat frequncy of 4 hertz what is the frequency of the unknown tuning fork?

The Attempt at a Solution



i have no clue please help me
 
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what is the relationship between any two fork frequencies sounded together and the beat frequency generated? (hint: look in your text and your lab documents)
 


Ouabache= the relation is when two similar frequencies are heard= a beat is generated

and freq of beat= freq1 -freq 2 therefore... my textbook doesn't have any sample questions that's y please help me with more direct answer.. or atleast one or two steps

one attempt i made was let unknown freq be x
thus x + 360 hz = beat freq of 2 hz
x+ 358 hz = beat freq of 4 hz

but i don't know if i can solve x unknown frequency now
 


The beat frequency depends on the difference, not the sum; as you correctly said initially.
You know the difference is 2 but you don't know which one is the higher.
So, the clue to that is to look at the one where the difference was 4.
 


if the difference is 4 hertz that means

the unknown frequency will be 362 hertz

because the formula is freq of beat = f2 - f1
thus difference of 4 hertz means 362- 358

is this correct please give me more hints I am stuck here
 


That's correct.
It is 2 more than 360 and 4 more than 358.
so 2=362-360 (beat frequ of 2)
and
4=362-358 (beat frequ of 4)
362 is the only frequency that satisfies both equations.
 


Idrees said:

Homework Statement



i have to find the unknown resonant frequency of a tuning fork??

Homework Equations



when this unknown is struck along a known freq of 360 hertz = you hear beat frequency of 2 hertz.. and when its struck alongside a known freq of 358 = you hear beat frequncy of 4 hertz what is the frequency of the unknown tuning fork?

An intuitive way to solve this...
When you strike a known fork against the unknown and you don't hear any beats at all, then their difference in frequency is zero |f2-f1|=0 or f1 = f2

When you were given the 2nd bit of information, where the known fork = 358Hz, the beat frequency "increased" to 4Hz, but you want the beats to decrease to zero..
So you know immediately, that the unknown frequency must be > 360Hz ..
For |360-f1| = 2Hz, f1 = 362Hz.
 
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