Finding Values of p for Convergence: (-1)^(n-1)/ n^p

  • Thread starter Thread starter remaan
  • Start date Start date
  • Tags Tags
    Convergence
Click For Summary

Homework Help Overview

The discussion revolves around determining the values of p for which the series \((-1)^{n-1}/n^p\) converges. The subject area is series convergence, particularly focusing on alternating series and p-series.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to identify the conditions for convergence, with some suggesting that since it resembles a p-series, p should be greater than 1. Others question this classification and the reasoning behind it.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the series and its classification. Some guidance has been offered regarding the need for clarity in reasoning, but no consensus has been reached on the correct approach to determine convergence.

Contextual Notes

There are indications of confusion regarding terminology and the classification of the series, which may affect the understanding of convergence criteria. Participants are encouraged to clarify their thoughts and reasoning processes.

remaan
Messages
132
Reaction score
0

Homework Statement


For what values of p is the series con.
(-1)^ (n-1)/ (n)^(p)


Homework Equations



In order for a p series to converge, p should be greater than 1

The Attempt at a Solution



So an = 1/ n^p

and p > 1

Is that right ?
 
Physics news on Phys.org
You're making so many abbreviations and omissions that it's hard to tell what you're thinking -- I think you even confused yourself because of it. Try again, but this time say what you're doing, and why.
 
I don't think so,, the only abbreviation is Con. which means Convergent

** Am trying to find the valu of p for which the series will converge

What I thought about is : becauce it 's a p-series , then p should be P greater than 1 ?

What do you think ??
 
remaan said:
becauce it 's a p-series
No it's not.
 
So, give a hint? !
 
Oh, you I mean this part is a p- series, the one I considered as an
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
8
Views
2K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 9 ·
Replies
9
Views
1K