Finding Vel. and Pressure of blood flow in vessel

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SUMMARY

The discussion focuses on calculating the average velocity and pressure of blood flow in a horizontal blood vessel with varying cross-sectional diameters. Given a wider diameter of 6.5 mm and a narrower diameter of 5.2 mm, the average velocity at cross-section A is 0.2 m/s with a pressure of 100 mmHg. Using Bernoulli's equation and the density of blood at 1060 kg/m³, the calculated pressure at cross-section B is 69.4 mmHg, while the average velocity at that section is determined to be 0.3125 m/s. The viscosity of blood, measured at 2.1 x 10-3 Pa.s, is noted but not incorporated into the final calculations.

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  • Understanding of Bernoulli's equation
  • Knowledge of fluid dynamics principles
  • Familiarity with blood viscosity and density values
  • Basic skills in algebra for solving equations
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This discussion is beneficial for students in physiology, medical professionals studying hemodynamics, and anyone interested in the principles of fluid dynamics as applied to blood flow in vessels.

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helping a relative with their final studying but its been a few years since I've taken intro phys

Suppose a blood vessel is horizontal and it has wide and narrow cross sections as shown in Fig 1. In the real life the edges are not sharp and we assume their effects are negligible. Suppose the diameter of the wider portion is d = 6.5 mm and the diameter of the narrower part is 4/5 of the wider part. The viscosity of blood is n = 2.1 x 10"3 Pa.s and L = 4 cm. At cross-section A the average velocity is 0.2 m/s and the pressure is 100 mmHg. The direction of the blood flow is from A to B.
a)Find the average velocity at cross section
b)Find the pressure at cross section B.


when worked it out i came to P=99.72mmHg and V=.3125m/s

thanks for the help
 

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I will ignore viscosity and use Bernoulli's equation,

p1 - p2 = rho(v2^2 - v1^2)/2

Using your numbers, and the density of blood of 1060 kg/m^3 (see http://hypertextbook.com/facts/2004/MichaelShmukler.shtml0

p2 = p1 - rho(v2^2 - v1^2)/2 = 100 - 1060(.3125^2 - .2^2)/2 = 69.4mmHg

I don't have a clue how we work viscosity into this problem but including it makes p1 even smaller? Your number seems too high?
 
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