Finding Velocity and Distance of a Block on a Frictionless Track

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The discussion focuses on calculating the velocity and distance of a block on a frictionless track after being propelled by a compressed spring. The spring has a constant of 5.7 kN/m and compresses 4.6 cm, with the block starting from rest. The conservation of energy principle is applied, equating kinetic energy (KE) to elastic potential energy (Ue) to find the block's speed as it leaves the track. The height from which the block falls is necessary to determine the horizontal distance traveled and the total speed upon impact with the ground. Clarification is needed regarding the rough area on the track, as friction would affect energy conservation calculations.
RAKINMAZID
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Conservation of Energy--please help me!

Homework Statement


A block is pushed against the spring with spring constant 5.7 kN/m (located on the left-hand side of the track) and compresses the spring a distance 4.6 cm from its equilibrium position. The block starts at rest, is accelerated by the compressed spring, and slides across a frictionless track except for a small rough area on a horizontal section of the track. It leaves the track horizontally, flies through the air, and subsequently strikes the ground. The acceleration of gravity is 9.8 m/s^2.

1) What is the speed v of the block when it leaves the track?

2) What is the horizontal distance x the block travels in the air?

3) What is the total speed of the block when it hits the ground?


Homework Equations



KE = (1/2)mv^2
Ue = (1/2)kx^2

The Attempt at a Solution



To find velocity I set KE equal to Ue (def. of conservation of energy)
(1/2)mv^2 = (1/2)kx^2
mv^2 = kx^2

v = sqrt [(kx^2)/m]
 
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That sounds right for (1). For (2) and (3) you need the height it falls, so I hope you've been given that. And I don't know what the deal with this rough area is. Have they given you any more information about that? Because if it slows the block down by friction, conservation of energy will be useless.
 

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