Finding Velocity of a bullet using springs and hanging masses

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Homework Help Overview

The problem involves designing a ballistic spring system to measure the speed of bullets using a spring and a hanging mass. The setup includes a bullet fired into a block suspended from a spring, with the goal of determining the bullet's velocity based on the spring's compression.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of energy conservation and Newton's laws to find the bullet's velocity. There are questions about the clarity of certain variables, such as the distance y, and concerns regarding energy loss during the collision. Some suggest using conservation of momentum instead of energy due to the complexities introduced by energy loss.

Discussion Status

The discussion is ongoing, with various interpretations of the energy conservation approach being explored. Some participants are questioning the assumptions made in the original poster's calculations, while others are suggesting alternative methods to analyze the problem.

Contextual Notes

There are concerns about the energy lost during the collision between the bullet and the block, which complicates the use of conservation of energy. The definitions of certain variables and their roles in the equations are also under scrutiny.

viciousp
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Homework Statement



You have been asked to design a "ballistic spring system" to measure the speed of bullets. A spring whose spring constant is k is suspended from the ceiling. A block of mass M hangs from the spring. A bullet of mass m is fired vertically upward into the bottom of the block. The spring's maximum compression d is measured.

Homework Equations


KEi + PEi = KEf +PEf
F= -kx

The Attempt at a Solution



I first used Newtons second law to find the the distance x the string is stretched, so:
Mg=k(x-d)
x= (Mg/k)+d

Then I used the energy law like so:
1/2(mb(Vb)2 +Mgy + 1/2(k)(x2) = Mg(y+d)

solving for Vb I get:

sqrt[(2Mgd-(k(d+Mg/k)^2))/m]

But I am pretty sure this is wrong, can someone help me
 
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I don't fully understand this
1/2(mb(Vb)2 +Mgy + 1/2(k)(x2) = Mg(y+d)
The distance y is not clear to me.
It seems to me that it should be
energy before = energy after
½mv² + ½kx² = Mgy + ½k(y-x)²
assuming that y is the amount M moves upward when the bullet hits
 
I used y as the height from the block to the ground
 
Okay, that makes sense but your formula does not include the energy stored in the spring after the collision.

Actually, I'm worried about the whole approach. The bullet will embed itself in the block, losing lots of energy to friction. We have no way to estimate this loss of energy so we can't use conservation of energy.

Recommend you use conservation of momentum in the collision of the bullet with the block. That should give you the speed and kinetic energy the bullet/block after the collision.
 

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