Finding Velocity of Connected Objects on Perpendicular Guide Rails

[luna02525]

Homework Statement

Two objects A and B are connected by a rigid rod that has a length 35 m. The objects slide along perpendicular guide rails. If A slides to the left with a constant speed 35.2379 m/s along the x-axis, find the velocity of B along the y-axis when the rod makes an angle 27* with the x-axis. Answer in units of m/s

Homework Equations

I'm not even sure.

The Attempt at a Solution

I attempted to find the velocity using the equation:

\vec{Ay}=\vec{A}sin\Theta

so,

\vec{Ay}=35sin(27*)

\vec{Ay}= 15.890 m/s

This, however, was not correct and I really am confused about what even would be correct or how I should go about solving the problem.

Thank you in advance for any help or information (or direction...).

 

[bel]

Since x^2+y^2=35, then \frac{y}{x}=tan(\psi). Then you can differentiate both sides of that by the time t. You know the required angle, and you know \frac{dx}{dt} as well.

 

[luna02525]

Since x^2+y^2=35, then \frac{y}{x}=tan(\psi). Then you can differentiate both sides of that by the time t. You know the required angle, and you know \frac{dx}{dt} as well.

so,

y=xtan\Theta

\frac{dy}{dt}=\frac{dx}{dt}tan27

\frac{dy}{dt}=35.2379*tan27 ?

 

[bel]

No, you have to make use of the relation x^2+y^2=35 as well and treat \psi as a function of time t.

 

[Astronuc]

I think one wants - x^2+y^2=35^2

 

[bel]

Oh right, it is the square of 35, silly me, how could I have forgotten? I apologise.