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Finding Voltage graph from current graph of capacitor

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  1. Jan 31, 2016 #1
    1. The problem statement, all variables and given/known data
    I am given the current flowing through a 2 micro-farad capacitor in the form of a graph, and I need to create a voltage graph from this.

    2. Relevant equations
    I = C dv/dt
    Q = VC

    3. The attempt at a solution
    The current graph is basic with a constant 4 mA from 0 to 4 microseconds and then -1 mA from 4 to 7 microseconds. I am a bit confused on how to proceed. Is the right way to go finding the total charge at each time interval, and then plugging into the Q = VC formula to find the voltage? So then the total charge would be the area under the current vs time graph? With this I am getting a voltage graph that has a constant positive slope until 4 microseconds, and then a smaller negative slope for the next 3 microseconds, Does this sound about right? Thanks for any help
     
  2. jcsd
  3. Jan 31, 2016 #2

    cnh1995

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    You are given the i-t relationship of the capacitor. You'll need to plot it on paper. What is the i-v relationship i.e. how would you write voltage across capacitor as a function of its current?
     
  4. Jan 31, 2016 #3
    Would the formula for the i-v relationship be v = c/(it)?
     
  5. Jan 31, 2016 #4

    cnh1995

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    No. You have i=Cdv/dt. This equation is in differential form. What should be done so that you'll get it as v as a function of i?
     
  6. Jan 31, 2016 #5
    Would you try to integrate both sides? With that wouldn't you end up with the equation Q = VC? This is the part where I'm confused
     
  7. Jan 31, 2016 #6

    cnh1995

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    Right.
    V=(1/C)∫i dt.
    You have i(t), don't you? Integrate it between the given time intervals and find V as a function of time.
    You do not need to take ∫i dt as Q.
     
  8. Jan 31, 2016 #7
    Okay, so with the numbers I gave above, i(t) would just be equal to .004A from 0 to 4 microseconds, making V(t) = (1/C) * .004t, and then the same for the next time interval, does that look right? Thank you for your help
     
  9. Jan 31, 2016 #8

    cnh1995

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    Yes. You can plot it accordingly. It will be a triangular wave (not symmetric).
     
  10. Jan 31, 2016 #9
    Great, I understand now. Thank you very much for your help
     
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