Finding Volume of Solid with Rectangle Cross-Sections | Geometry Homework

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The volume of the solid with a base defined by the region bounded by the lines x=0, y=0, and y=3*(4-x)^(1/2) is calculated using the definite integral from 0 to 4. The cross-sections perpendicular to the x-axis are rectangles with heights equal to two times their bases. The formula used for the volume is 4∫2*(3(4-x)^(1/2))^2 dx from 0 to 4, which simplifies to 2b^2, confirming the approach is correct for this geometry problem.

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Homework Statement


Find the volume of the solid whose base is the region bounded by the lines x=0, y=0, and y= 3*(4-x)^1/2 and whose corss-sections perpendicular to the x-axis are rectangles whose heights are two times the base.


Homework Equations



b*h


The Attempt at a Solution



The function ends at 4, so limits are 0 to 4.
Height is 2x base
so we have 2b^2

4
∫2*(3(4-x)^1/2)^2
0

And then solve the definite integral, I believe that is correct.
 
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Chas3down said:

Homework Statement


Find the volume of the solid whose base is the region bounded by the lines x=0, y=0, and y= 3*(4-x)^1/2 and whose corss-sections perpendicular to the x-axis are rectangles whose heights are two times the base.


Homework Equations



b*h


The Attempt at a Solution



The function ends at 4, so limits are 0 to 4.
Height is 2x base
so we have 2b^2

4
∫2*(3(4-x)^1/2)^2
0

And then solve the definite integral, I believe that is correct.

Looks correct to me as well.
 

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