Finding Volume Triple Integral

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Homework Statement


Find the volume of area the area bounded by x^2+y^2=36, z=x and below the xy plane


Homework Equations





The Attempt at a Solution


I did a triple integral dzdxdy,
where dz is bound between x and 0
dx is bound between 0 and (36-y^2)^(1/2)
and dy is bound between 0 and 6
and got the incorrect answer.
Where did I go wrong here?
 
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You got only half of the correct value, right? Try to draw a diagram of what your bounds correspond to.
Btw, it's not 'dx' etc. that's bound. It's x etc.