Find The Volume; Triple Integrals

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SUMMARY

The volume of the solid enclosed by the paraboloids z = (x^2 + y^2) and z = 32 - (x^2 + y^2) can be effectively calculated using cylindrical coordinates. The correct limits for the radial coordinate r are from 0 to 4, not 1, as initially stated. The integration should be performed over the volume defined by the inequalities 0 < r < 4, 0 < θ < 2π, and r < z < 32 - r. This approach leads to the correct volume calculation, which is 32π.

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  • Cylindrical coordinates in multivariable calculus
  • Understanding of triple integrals
  • Knowledge of paraboloid equations
  • Integration techniques for volume calculation
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  • Study the application of cylindrical coordinates in triple integrals
  • Practice solving volume problems involving paraboloids
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withthemotive
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Find the volume of the solid enclosed by the paraboloids z = (x^2 + y^2 ) and z = 32 − ( x^2 + y^2) .To make this problem easier to look at I resorting to making it into cylindrical coordinates.
{r, theta, z| 0< r< 1, 0<theta<2pi, r< z< 32-r}

Every time I solve for this I end up getting 31pi and I'm being told it's constantly wrong.
 
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Welcome to PF!

withthemotive said:
Find the volume of the solid enclosed by the paraboloids z = (x^2 + y^2 ) and z = 32 − ( x^2 + y^2) .

0< r< 1

Hi withthemotive! Welcome to PF! :smile:

No, r goes from 0 to … ? :wink:

(but isn't it easier just to take horizontal slices of thickness dz, and just integrate once, over z?)
 


tiny-tim said:
Hi withthemotive! Welcome to PF! :smile:

No, r goes from 0 to … ? :wink:

(but isn't it easier just to take horizontal slices of thickness dz, and just integrate once, over z?)

LOL...oops.
I was looking at a similar problem on here, I think I might have figured it out now.
 

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