How Is the Work Done by Friction Calculated on an Inclined Plane?

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To calculate the work done by friction on a 500 kg crate on a 30° incline with a 4000 N horizontal force, first determine the work done by the applied force over 3.0 m. The change in kinetic energy, due to the velocity increase from 1.0 m/s to 2.8 m/s, must also be calculated. Additionally, consider the work done against gravitational potential energy as the crate moves up the incline. Subtract the total work done by the applied force and the energy changes from the work done against friction to find the frictional work. This method effectively isolates the work done by friction.
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a 500 kg crate is on a rough surface inclined at 30°. A constant external force
P = 4000 N is applied horizontally to the crate. The force pushes the crate a distance of 3.0 m up the
incline, in a time interval of 9.2 s, and the velocity changes from ν1 = 1.0 m/s to ν2 = 2.8 m/s. The
work done by the friction force is closest to:

I have no idea how to start this. I tried just using the regular work equation or conservation of energy and did not find the answer.
 
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You are posting this in the wrong forum.

Anyway, find the work done by the force, then find the work done to bring it from a lower to a higher region, to increase the velocity, etc. , and just minus off all of them to find the work done to overcome friction.
 

Thread 'Mousetrap Car Energy efficiency'

For simple comparison, I think the same thought process can be followed as a block slides down a hill, - for block down hill, simple starting PE of mgh to final max KE 0.5mv^2 - comparing PE1 to max KE2 would result in finding the work friction did through the process. efficiency is just 100*KE2/PE1. If a mousetrap car travels along a flat surface, a starting PE of 0.5 k th^2 can be measured and maximum velocity of the car can also be measured. If energy efficiency is defined by...
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