In problem 11, determine by inspection at least two solutions of the given initial-value problem.
11. dy/dx = 3y^(2/3) , y(0)=0
The Attempt at a Solution
I can't figure out what they mean by inspection, I have no examples to go off from.
If i make it f(x,y)= 3y^(2/3) then the derivative (df/dy) would be 2/(y^(1/3))
then y could not = 0 which means there is not a guaranteed unique solution.
Now how do I go on to get the solutions :/?
Book says y = 0 and y= x^3 is the answer.