- #1

- 61

- 3

i'm having trouble with this question,

x y' - y = x

^{2}cosx

the solution is

y= xc + xsinx

and we are asked to solve the equation in the following two cases,

1, y(0)=0

and 2, y(0) = 1

but applying these conditions to the general solution gives no information,

in both cases its 0 = 0, so doing this you cant find the constant.

is there another way to solve the equation for these conditions?

even mathematica can't solve it, but it was a question in a test and i was marked wrong for saying neither cases can be solved (as in the constant cant be found)

thanks