Flow Around a Cylinder with Linear Vortex and Points of Stagnation

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SUMMARY

The discussion focuses on calculating the flow around a cylinder of radius ##a## influenced by a linear vortex ##\Gamma## located at point ##z=b##, where ##b>a##. The complex potential of the vortex is defined as $$\omega_{vortex} = \frac{\Gamma}{2\pi i}\ln{z}$$, and the Milne-Thomson circle theorem is applied to derive the complex potential with boundary conditions for the cylinder. The main challenge highlighted is the difficulty in separating the real and imaginary components of the logarithmic terms to extract the velocity potential ##\Phi## and the stream function ##\Psi##.

PREREQUISITES
  • Understanding of complex potential theory in fluid dynamics
  • Familiarity with the Milne-Thomson circle theorem
  • Knowledge of logarithmic functions in complex analysis
  • Ability to perform substitutions in complex variables
NEXT STEPS
  • Study the application of the Milne-Thomson circle theorem in fluid dynamics
  • Learn about the separation of variables in complex potentials
  • Explore methods for finding velocity potentials and stream functions from complex potentials
  • Investigate the use of substitutions in complex analysis for simplifying logarithmic terms
USEFUL FOR

Students and professionals in fluid dynamics, particularly those working with potential flow theory and complex analysis. This discussion is beneficial for anyone tackling problems involving vortex flows and stagnation points around cylindrical objects.

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Homework Statement


Find the flow around a cylinder with radius ##a## generated by linear vortex ##\Gamma## in point ##z=b##. Find points of stagnation. Also ##b>a##

Homework Equations


Complex potential of vortex: $$\omega_{vortex} = \frac{\Gamma}{2\pi i}\ln{z}$$
Milne-Thomson circle theorem: $$\omega (z) = f(z) + \overline{f(\frac{a^2}{\overline{z}})}$$

The Attempt at a Solution


Here my ##f(z)## is: $$f(z)=\frac{\Gamma}{2\pi i}\ln{(z - b)}$$
Applying circle theorem: $$\omega (z) = f(z) + \overline{f(\frac{a^2}{\overline{z}})} = ... = \frac{\Gamma}{2\pi i}\bigg( \ln{(z-b)} - \ln{(\frac{a^2}{z} - b)} \bigg)$$
which is, I assume, the complex potential with boundary conditions for cylinder. But how am I supposed to find the flow now? I tried rotation of rotation but it's pointless. I'd be really gratful for help or hints.
 
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I have little clue of what you are talking about (my ignorance), but if that is a complex potential then the real part of the function is the velocity potential and to find the velocity field you just take the gradient of the potential. Hope it is what you are looking for.
 
Yes, but the problem is that logarithms are centered in points other than ##z=0## and I'm wondering if I'm trying to do it wrong, because I can't separate real and imaginary terms in order to get ##\Phi## - velocity potential and ##\Psi## - stream function,
 

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