Fluid mechanics conservation of momentum problem

Click For Summary

Discussion Overview

The discussion revolves around a fluid mechanics problem involving the conservation of momentum in fluid flow through a 180-degree bend in a pipe. Participants explore how to determine the force applied on the flanges connecting the bend to straight pieces of pipe, considering various parameters such as diameter, length, weight flow rate, and pressure at the inlet and outlet.

Discussion Character

  • Homework-related, Technical explanation, Exploratory

Main Points Raised

  • One participant outlines the problem, noting the need to apply the Reynolds transport theorem and define a control volume around the bend to analyze the forces on the flanges.
  • Another participant suggests using the linear momentum equation to find the flange reaction force, questioning whether the inlet and outlet pressures are equal.
  • A subsequent post clarifies that the inlet pressure is greater than the outlet pressure, indicating potential energy loss in the pipe, but the participant is uncertain about how to incorporate this into their calculations.
  • A later reply mentions that the problem was resolved, confirming that the mass flow rate and velocity are the same, and attributes the pressure difference to gravitational effects, highlighting a realization about the pipe's orientation.

Areas of Agreement / Disagreement

Participants express differing views on the implications of pressure differences and energy loss in the system. While one participant resolves their issue, the discussion does not reach a consensus on the initial approach to the problem.

Contextual Notes

Participants note the importance of understanding the orientation of the pipe and how it affects pressure differences, but there are unresolved aspects regarding the application of the linear momentum equation and the implications of energy loss.

ehilge
Messages
160
Reaction score
0

Homework Statement


The problem involves fluid flow through a 180 degree bend in a pipe. I am trying to find out the force applied on the flanges connecting the bend to straight pieces of pipe. I am given information on the diameter of the pipe, the length of the pipe, weight flow rate, and pressure at both the inlet and outlet of the 'U'

Homework Equations


The Reynolds transport theorem using linear momentum.

The Attempt at a Solution


I need help figuring out how to approach the problem. A control volume can be defined surrounding the 'U' and cutting through the pipe at the flanges. Since there is only one inlet, one outlet, and no change in volume, the mass flow rate in must be the same as out. The area of the pipe is the same on each side, so it follows that the velocity of the fluid must be the same on each side. But continuing with this logic, the force on each flange would be the same in equal and opposite directions using the Reynolds transport theorem. And I don't see how that can be plausible considering the type of information in the problem statement and it appears that some energy is lost in the pipe. So my question is, where is the flaw in my logic?
 
Physics news on Phys.org
Use the linear momentum equation to find the flange reaction force. Looks like everything is in the x-direction. Is P_inlet=P_outlet? Velocities and unit vectors are in the same so angle between them is 0.
 
RTW69 said:
Use the linear momentum equation to find the flange reaction force. Looks like everything is in the x-direction. Is P_inlet=P_outlet? Velocities and unit vectors are in the same so angle between them is 0.

I'm sorry, I failed to specify that, Pin > Pout which I guess is really the kicker here because that would imply energy is lost in the pipe somewhere, but I'm not sure how to work that in.
 
if anyone is curious, I got the problem resolved today. The mass flow rate and velocity are indeed the same, and gravity accounts for the difference in pressure. I didn't realize what the orientation of the pipe was.
 

Similar threads

Replies
15
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 8 ·
Replies
8
Views
19K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
31
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 24 ·
Replies
24
Views
6K
  • · Replies 1 ·
Replies
1
Views
3K