1. The problem statement, all variables and given/known data Given: water at 20°C flows through a 3cmID smooth brass tube at 0.002 m^3/s. 2. Relevant equations V=Q/A f=64/Re Re=VD/(nu) 3. The attempt at a solution V=Q/A=(0.002 m^3/s)/((∏/4)*(0.03 m)^2) = 2.829 m/s Re=VD/(nu) = (2.829 m/s)*(0.03 m)/(1x10^-6 m^2/s)=84882.64 f=64/Re=0.0075 I know this is wrong for two reasons: 1. The numeric answer is in the back of the book: 0.0185 2. Looking at the Moody Diagram: there is no f value on the chart below 0.008. Any help in finding my mistake would be appreciated. Thank you.