Fluid Powers: Determine what class lever I'm using

[Bsmith072]

I need help figuring out which formula to use to find what class lever I am using in a 10 ton log splitter circuit. The lever is 16 inches long and I am applying 100 pounds of force on the lever which is connected to a cylinder 5 inches in diameter, 24 inch stroke, and a 2 inch rod diameter. My teacher says it's in our book but didn't say specifically which formula it is and I just can't figure it out by looking at them all.

 

[Simon Bridge]

Welcome to PF;
Where is the pivot in relation to the load and the applied force?
Look at the diagrams for different class levers in your book and compare.

 

[Bsmith072]

Ok so it looks like a class 3 lever. The rod of the piston comes up and touches the middle. not quite sure if you can tell from the picture but I'm pretty sure it looks like a class 3

 

[Simon Bridge]

I've personally never used the class system for levers... I just use the sum of torques: then I only need to remember one equation.

 

[Bsmith072]

OK. My teacher didn't actually go over all of this with us so we're flying blind trying to learn for ourselves. Thanks for the help

 

[Simon Bridge]

If you know about torque (moments) you can check the equation.
Locate the pivot, sketch the force vectors in.

 

[Bsmith072]

I also have to figure out the pressure at 3 different points and all the 3 points are between 2 cylinders one of which I believe is an intensifier if I'm looking at the problem correctly. I just need an equation to go off of.