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**1. There is a cylinder fitted with a piston, the piston has a mass m1 of 0.50 kg and a radius of 2.50 x 10^-2 m. The top of the piston is open to the atmosphere. The pressure underneath the piston is maintained at a reduced (but constant) value by means of the pump. As shown, a rope of negligible mass is attached to the piston and passes over two massless pulleys. The other end of the rope is attached to a block that has a mass of m2 = 9.5 kg. The block falls from rest down through a distance of 1.25 m in 3.30 s. Ignoring friction, find the absolute pressure beneath the piston.**

m1 = .5 kg

m2 = 9.5 kg

R = 2.5x10^-2 m

d =1.25 m

T = 3.30s

P2 = P1 + pgh

P=F/Area

acceleration = V2-V1/T2-T1

F=MA

(m1+m2)a-m2*g+m1*g+Patm = P2

didn't work, I tried comparing the amount of force required to oppose the force of gravity in order to make the descending block have an acceleration that matches the calculated acceleration for the falling block. Any help on this problem would be most appreciated, I have a few more stumpers if anyone thinks they know thermodynamics well enough

m1 = .5 kg

m2 = 9.5 kg

R = 2.5x10^-2 m

d =1.25 m

T = 3.30s

## Homework Equations

P2 = P1 + pgh

P=F/Area

acceleration = V2-V1/T2-T1

F=MA

## The Attempt at a Solution

(m1+m2)a-m2*g+m1*g+Patm = P2

didn't work, I tried comparing the amount of force required to oppose the force of gravity in order to make the descending block have an acceleration that matches the calculated acceleration for the falling block. Any help on this problem would be most appreciated, I have a few more stumpers if anyone thinks they know thermodynamics well enough