Fluids-blow across top of straw to draw up olive oil

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To draw olive oil upward through a straw by blowing across its top, one must calculate the minimum air speed required using fluid dynamics principles. The pressure difference needed to lift the oil column is determined by the formula rho*g*h, where rho is the density of the olive oil, g is the acceleration due to gravity, and h is the height of the oil column. The relevant equation incorporates initial and final pressures and velocities at both ends of the straw. The initial air velocity at the bottom of the straw is zero, simplifying the calculations. Understanding these principles allows for accurate determination of the air speed necessary to achieve the desired effect.
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Homework Statement



You try to remove olive oil from a glass by blowing across the top of a vertical straw immersed in the olive oil. What is the minimum speed you must give the air at the top of the straw to draw olive oil upward through a height of 1.5 cm?
(Note: The density of olive oil, if you need it is 920 kg per cubic meter.)

Homework Equations



P1 + .5*density*v1^2 + density*g*y1 = P2 + .5*density*v2^2 + density*g*y2


The Attempt at a Solution



P1 + .5*density*v1^2 + density*g*y1 = P2 + .5*density*v2^2 + density*g*y2
P1 = .5*density*v2^2 + density*g*y2
V2 = 14.83 m/s
V2 is close, but not right; I'm not sure how to find P2. What do I need to do different?
 
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I don't understand your calculations. How did you get from P1 = .5*density*v2^2 + density*g*y2 to v2=14.83 m/s?

You can calculate the pressure difference between the top and bottom of the straw that's needed to support the olive oil column; it's just rho*g*h. Then, you can apply the equation P1 + .5*density*v1^2 + density*g*y1 = P2 + .5*density*v2^2 + density*g*y2 with the left side representing the bottom of the straw and the right side representing the top. v1 would be 0, since the air at the bottom isn't moving, and you've just calculated P1-P2.
 
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