Flywheel Kinetic Energy in Delivery Trucks

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SUMMARY

The kinetic energy of a flywheel used in delivery trucks is calculated using the formula K = 1/2 Iω², where I is the moment of inertia and ω is the angular velocity. For a solid homogeneous cylinder with a mass of 550 kg and a radius of 0.65 m, rotating at 960 rad/s, the kinetic energy is determined to be 5.35 x 107 joules. Additionally, with an average power requirement of 9.3 kW, the truck can operate for approximately 10.5 minutes between charges.

PREREQUISITES
  • Understanding of rotational dynamics and kinetic energy formulas
  • Familiarity with the moment of inertia calculation for solid cylinders
  • Basic knowledge of power and energy conversion
  • Ability to convert angular velocity from radians per second to linear velocity
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  • Learn about energy storage systems in electric vehicles
  • Research the efficiency of flywheel energy storage compared to batteries
  • Explore the implications of power requirements on vehicle range and performance
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Mechanical engineers, automotive engineers, students studying physics, and professionals involved in electric vehicle technology will benefit from this discussion.

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Homework Statement


Delivery trucks that operate by making use of energy stored in a rotating flywheel have been used in Europe. The trucks are charged by using an electric motor to get the flywheel up to its top speed of 960 rad/s. One such flywheel is a solid homogenous cylinder, rotating about its central axis, with a mass of 550 kg and a radius of 0.65 m. What is the kinetic energy of the flywheel after charging?

If the truck operates with an average power requirement of 9.3 kW, for how many minutes can it operate between charging?



Homework Equations


K = 1/2Iw^2
I = 1/2mr^2

The Attempt at a Solution


K = 1/2 * (.5 * 550 * .65^2) * 960^2 = 5.35 x 10^7
I a, getting a really huge number I wanted to make sure I am doing it right.
 
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Well convert radians per second to metres per second.

Then K = 0.5 (m) (v)^2
 

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