Hard Rotational Kinetic energy question (Flywheel)

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Homework Help Overview

The problem involves calculating the rotational kinetic energy of a flywheel after being subjected to a torque over a specified time period. The flywheel has a mass of 100 kg and a diameter of 80 cm, with the torque applied being 5 Nm. The initial state of the flywheel is at rest.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of the moment of inertia and question the use of gravitational acceleration in the formula. There are inquiries about the relationship between the radius and diameter of the flywheel, as well as the units of the calculated moment of inertia.

Discussion Status

Some participants have provided feedback on the calculations presented, noting potential errors and confirming that the method appears generally acceptable. There is an ongoing exploration of the assumptions made regarding the parameters of the problem.

Contextual Notes

Participants are addressing potential discrepancies in the problem setup, such as the interpretation of the flywheel's dimensions and the units used in calculations. There is an emphasis on ensuring that the information given aligns with the requirements of the formulas being applied.

orangeincup
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Homework Statement


A motor imposes 5 Nm on a shaft of a 100kg flywheel which is 80cm(diameter)

What is the rotational kinetic energy after 10 mins? assuming the flywheel was at rest and the mass moment of inertia of the shaft is negligble.


Homework Equations


Ig=1/2 * mr^2
RKE=1/2*Ig*ω^2
T=Ig*Ac
ω=ω0+ Ac*t

The Attempt at a Solution


Can someone look at this and tell me what I should change? I have no idea if it is right or not.

Solving for moment of inertia: Ig= 1/2 * m*r^2, Ig=1/2*(100kg*9.81m/s^2)*(.8m/2)^2
Ig=78.4(not sure units)

Solving for acceleration:
T=Ig*Ac
5/78.4=Ac
0.063=Ac (not sure units)

Solving for ω:
ω=ω0+Ac*t
ω=0+0.063*(10minutes*60)
ω=37.80 rad/s

Solving for RKE:
RKE=1/2*Ig*ω^2
RKE=56010.5 J
 
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orangeincup said:
Solving for moment of inertia: Ig= 1/2 * m*r^2, Ig=1/2*(100kg*9.81m/s^2)*(.8m/2)^2
Ig=78.4(not sure units)
Why did you multiply by g? You want the mass, not the weight.

Other than that, your method looks OK.
 
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Doc Al said:
Why did you multiply by g? You want the mass, not the weight.

Other than that, your method looks OK.

Opps. Thank you.
 
orangeincup said:

Homework Statement


A motor imposes 5 Nm on a shaft of a 100kg flywheel which is 80cm(diameter)
Solving for moment of inertia: Ig= 1/2 * m*r^2, Ig=1/2*(100kg*9.81m/s^2)*(.8m/2)^2
Ig=78.4(not sure units)

Make sure the information given in the problem matches the information required for your formula.

Is the radius of the flywheel the same as its diameter?

If you are not sure of the units of your answer, calculate them according to the formula you are using.

If inertia = 1/2*m*r^2, then the units will be kg (mass) * m^2 (radius^2), or kg-m^2

orangeincup said:
Opps. Thank you.

Should be 'Oops'. 'Opps' rhymes with 'tops', while 'oops' rhymes with 'loops'.
 
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SteamKing said:
Is the radius of the flywheel the same as its diameter?
It was divided by 2.
 

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