How Do You Calculate the Kinetic Energy of a Flywheel?

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SUMMARY

The kinetic energy of a flywheel can be calculated using the formula KE = (1/2)Iω², where I is the moment of inertia and ω is the angular velocity. In this case, with a moment of inertia of 0.32 kg/m² and an angular velocity of 120 rad/s, the kinetic energy is KE = (1/2)(0.32)(120)², resulting in a value of 2304 Joules. The discussion emphasizes the importance of using rotational dynamics equations rather than linear ones when dealing with rotating objects.

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Homework Statement


Q: A flywheel of moment of inertia 0.32kg/m^2 is rotated steadily at 120rad/s by a 50W electric motor. Find the kinetic energy of the flywheel.

Homework Equations


What is the best way to work this out? Am I using the right equations?
Can I simply substitute the angular rotation (120rad/s) instead of the velocity v in KE=(1/2)mv^2

The Attempt at a Solution


This is what I tried doing:
KE = (0.5).(m).(120)^2 but I still don't know the mass
Tried to use ω = v/r but I was not given the radius
To use power, I tried P = F.v -> P = m.a.v but I get stuck again because of mass and acceleration.Where: ω = angular speed; v = linear velocity; m = mass; P = Power; F = force; KE = Kinetic Energy; a = acceleration
 
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The flywheel is only spinning, not translating. Use the appropriate formula.
 
You've been given some information that you've not used.
Why do you think you were given it?

You've got the linear formula, the principle is the same for rotation. You just need to use the rotational analogues.
 

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