Force acting on wedge and block

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Joza
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http://i257.photobucket.com/albums/hh216/Megatallica/wedge.jpg


When the wedge is pushed by the constant force, how big must the force be in magnitude to keep the box at a constant height above the table. Assume no friction.

Well the force pulling the box down is a component of its gravity right? So this force is equal to (mg)/(sin alpha). A force, caused by the force accelerating the wedge must cancel this force out right? But I am having trouble identifying where it is coming from and what way it is acting on the block...
 
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