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Force acting on wedge and block

  1. Jan 2, 2008 #1

    When the wedge is pushed by the constant force, how big must the force be in magnitude to keep the box at a constant height above the table. Assume no friction.

    Well the force pulling the box down is a component of its gravity right? So this force is equal to (mg)/(sin alpha). A force, caused by the force accelerating the wedge must cancel this force out right? But Im having trouble identifying where it is coming from and what way it is acting on the block....
  2. jcsd
  3. Jan 2, 2008 #2

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