Force acting on wedge and block

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SUMMARY

The discussion focuses on the forces acting on a wedge and block system, specifically determining the magnitude of the force required to maintain the box at a constant height above the table. It is established that the downward force on the box is a component of its gravitational force, calculated as (mg)/(sin α), where m is the mass and α is the angle of the wedge. The force exerted by the wedge must counteract this gravitational component to keep the box stationary. The conversation highlights the need to identify the direction and source of the force acting on the block.

PREREQUISITES
  • Understanding of basic physics concepts, specifically forces and motion.
  • Familiarity with trigonometric functions, particularly sine.
  • Knowledge of gravitational force calculations.
  • Concept of equilibrium in physics.
NEXT STEPS
  • Study the principles of static equilibrium in physics.
  • Learn about the forces acting on inclined planes and wedges.
  • Explore the concept of components of forces in two dimensions.
  • Investigate the role of friction in wedge and block systems.
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Physics students, educators, and anyone interested in understanding the mechanics of forces in wedge and block systems.

Joza
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http://i257.photobucket.com/albums/hh216/Megatallica/wedge.jpg


When the wedge is pushed by the constant force, how big must the force be in magnitude to keep the box at a constant height above the table. Assume no friction.

Well the force pulling the box down is a component of its gravity right? So this force is equal to (mg)/(sin alpha). A force, caused by the force accelerating the wedge must cancel this force out right? But I am having trouble identifying where it is coming from and what way it is acting on the block...
 
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