Force and Friction: Explaining Intuitively Why 1000N.

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SUMMARY

The discussion centers on the relationship between force, friction, and normal force, specifically addressing the equation F = μN, where N represents the normal force. When an object with a mass of 10 kg is placed against a wall with a coefficient of friction of 0.1, the required force to keep it in place is calculated as 1000 N, which seems counterintuitive compared to the gravitational force of 100 N. The conversation clarifies that the normal force must be applied perpendicular to the frictional force, necessitating a greater force to counteract the object's weight on a slippery surface.

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Sachin Saraogi
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We know that force * coeff. of friction = m * g. . It does not make sense. Pls read details. This is when force is applied perpendicular to the direction of friction. But suppose we say that m = 10 kg, g = 10 m/s2, coeff. of friction is 0.1. Then by formula it says that force required to keep the object against the wall will be 1000 N. How does this make sense? I mean the force required to lift the object without any support is just m*g = 100 N. Pls explain this so that it makes intuitive sense...
 
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Sachin Saraogi said:
We know that force * coeff. of friction = m * g. . It does not make sense.
Of course it doesn't, it is nonsense.

This is not correct ... the usual equation is ##F=\mu N## where "N" is the magnitude of the contact force between the surfaces.
Where that is a horizontal flat surface, ##N=mg## ... which is to say it's the weight of the object.

Pls read details. This is when force is applied perpendicular to the direction of friction. But suppose we say that m = 10 kg, g = 10 m/s2, coeff. of friction is 0.1. Then by formula it says that force required to keep the object against the wall will be 1000 N. How does this make sense?
Oh you mean that you are applying the normal force?

If you want friction to hold a box against it's weight, on a wall that slippery, then sure ... you will need a lot of force... especially if you are only applying the force horizontally.

Please see:
http://hyperphysics.phy-astr.gsu.edu/hbase/frict.html
http://www.engineeringtoolbox.com/friction-coefficients-d_778.html
 
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