Force and Newtons law of motion

Click For Summary

Homework Help Overview

The discussion revolves around a physics problem involving a car rolling on a level street, with a focus on the forces acting on it, particularly friction, and how these relate to the car's stopping distance. The subject area includes concepts from dynamics and the work-energy theorem.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between frictional force and acceleration, questioning how to set up the equations correctly. There are attempts to apply the work-energy theorem and kinematic equations to find the stopping distance, with some participants expressing confusion about the forces involved and the correct application of work done.

Discussion Status

The discussion is ongoing, with participants providing suggestions and clarifications. Some guidance has been offered regarding the use of the work-energy theorem, but there remains a lack of consensus on the correct approach and understanding of the forces at play.

Contextual Notes

Participants are grappling with the implications of kinetic friction and the absence of an applied force, which complicates their calculations. There is also a mention of needing more detailed instructions, indicating a gap in understanding the concepts involved.

pat666
Messages
703
Reaction score
0

Homework Statement


your car rolls on a level street at 50km/h. the coefficient of kinetic friction is 0.023. how far will the car go before stopping. (no breaking.)


Homework Equations





The Attempt at a Solution


F_fric=0.226m
F_a=(-1250/s)*m
i need to make F_a-F_fric equal to something to solve for s, the m's will cancel. I have no idea what it will equal since its not in equilibrium...
 
Physics news on Phys.org
hi pat666! :wink:

use work done and the work-energy theorem :smile:
 
kk ill give that a whirl and tell you if i still can't do it... thanks
 
Hey, i still can't get this i tried finding the net work which i got -1250m J and then W=F/x with F=(-1250m)/x-0.226m. i got the acceleration (for F=ma) using kinematic equations.?
 
pat666 said:
Hey, i still can't get this i tried finding the net work which i got -1250m J and then W=F/x with F=(-1250m)/x-0.226m. i got the acceleration (for F=ma) using kinematic equations.?

Sorry, I don't understand any of that. :redface:

What is the energy? what is the force ?

If the distance is d, what is the work done ?
 
I just found the net work using 1/2mv^2-1/2mu^2. then i used W=F/x, to find the Force i just found the Force from friction and the "applied force". I might be doing something completely wrong, could you give me some more detailed instructions please.
 
It's W=Fx, not W=F/x. Also, there's no applied force; the force on the car is just the force of friction.
 
ok that's where i screwed up. thanks...
 

Similar threads

  • · Replies 25 ·
Replies
25
Views
2K
Replies
3
Views
2K
Replies
13
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
4K
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
930
  • · Replies 6 ·
Replies
6
Views
2K