Force Applied at an Angle to an Object on Frictionless Surface

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The problem involves a block sliding on a frictionless surface with a force of 20 N applied at a 30° angle. The relevant equation is F=ma, where the force components must be considered. The user initially calculated the acceleration as 3.46 m/s² by only accounting for the horizontal component of the force. However, they overlooked the total force applied, leading to the correct acceleration being 7.5 m/s². The discussion highlights the importance of considering all forces when solving physics problems.
jpsmith394
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Homework Statement


The horizontal surface on which the block slides is frictionless. If F = 20 N and M = 5.0 kg, what is the magnitude of the resulting acceleration of the block? The force is applied 30° to the horizontal.


Homework Equations


F=ma


The Attempt at a Solution


I began by ignoring the weight and normal force in the vertical axis (y-axis) because the surface is frictionless. Then my next step is to separate the force into compenets with F_{x}=Fcos\theta

Therefore:
ƩF_{x}=Fcos\theta = ma_{x}

So:
a_{x}=\frac{Fcos\theta}{m}

And using the given numbers I got a solution of 3.46\frac{m}{s^2}
But the online system I am using shows the correct answer as 7.5\frac{m}{s^2}
 

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hi jpsmith394! welcome to pf! :smile:

erm :redface: … you forgot the other F, in front! :wink:
 
tiny-tim said:
hi jpsmith394! welcome to pf! :smile:

erm :redface: … you forgot the other F, in front! :wink:

Oh gosh I see now, I was just stuck thinking it was just a single force

Thanks,
James
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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