Force between two charged particles

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Two similarly charged particles are released from a distance of 3.2*10^-3 m, with accelerations of 7.0 m/s² and 9.0 m/s², and the mass of the first particle is given as 6.3*10^-7 kg. The force exerted by each particle can be calculated using F=ma, leading to the equation m2 = (m1*a1*r²)/(G*m1 + a2*r²) for the second particle's mass, resulting in a value of 4.31*10^-7 kg. The discussion emphasizes that the forces between the particles are equal and opposite, allowing the use of Newton's second law. For determining the charge of each particle, the formula F = k*q²/r² is suggested, with clarification that only one force should be used in the calculation, not a factor of two. The conversation highlights the importance of understanding the interactions between charged particles in this context.
hk4491
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Homework Statement



Two particles with a similar charge are held at a distance of 3.2*10^-3 m and then released. The acceleration of the first particle is measured at 7.0 m/s^2, and for the second at 9.0 m?s^2. The mass of the first particle is 6.3*10^-7. What is the mass of the second particle?


Homework Equations



F=ma F=G*m1*m2/r^2


The Attempt at a Solution



F1=m1a1 F2=m2a2 (where F1 and F2 are the forces exerted by each particle respectively)

F1 - F2 = G*m1*m2/r^2

(since the particles are similarly charged, they would have forces pointing in opposite directions)

after substitution and making m2 the subject of the formula:

m2 = (m1*a1*r^2)/(Gm1 + a2r^2)

which gives: m2 = 4.31*10^-7

I am not so sure if the method I used is completely correct, can someone please tell me?
 
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hk4491 said:

Homework Equations



F=ma F=G*m1*m2/r^2
The particles are charged. Do you really think that they will primarily feel a gravitational attraction? And to you really need to calculate the value of the force, or isn't there one of Newton's law you can use?
 
Hi, thanks for replying. Are the forces produced by the two particles equal? Because then I can use Newton's second law as such:

m1a1=m2a2

Would this be correct?
 
Yes, this is waht I was hinting at. If particle 1 feels a force from particle 2, then particle two must feel an equal and opposite force from particle 1.
 
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In the second part they're asking me to find the charge of each particle. I know I should use this formula:

F = k.q^2/r^2

and solve for q. As my force should I substitute 2*ma, since there are two particles, or is one enough?
 
hk4491 said:
In the second part they're asking me to find the charge of each particle. I know I should use this formula:

F = k.q^2/r^2

and solve for q. As my force should I substitute 2*ma, since there are two particles, or is one enough?
In essence, there are not two forces, but one that affects two particles, albeit in different directions. So no factor of two.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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