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- Homework Statement
- A conveyer belt is rolling in a factory on the equator. The top is going east at double the earth's linear velocity and the bottom is stationary relative to the center of the earth. What will be the acceleration due to gravity?

- Relevant Equations
- F=m×a=mv^2/R => a=v^2/R

v1=460m/s×2, v2=0

m1=m2=5kg

R=6378km

a1=460m×460m/s/s/6378/km/1000/m×km=0.13m/s/s

a2=0

F1=m1×a1=0.66kg×m/s/s

F2=m2×a2=0

G=9.81m/s/s

F3=(m1+m2)×G=98.1kg×m/s/s

(F3-F1)/10/kg = 9.744m/s/s

Where the heck did I go wrong?

m1=m2=5kg

R=6378km

a1=460m×460m/s/s/6378/km/1000/m×km=0.13m/s/s

a2=0

F1=m1×a1=0.66kg×m/s/s

F2=m2×a2=0

G=9.81m/s/s

F3=(m1+m2)×G=98.1kg×m/s/s

(F3-F1)/10/kg = 9.744m/s/s

Where the heck did I go wrong?