Force between two parallel wires

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SUMMARY

The discussion centers on calculating the force between two parallel wires carrying current, specifically a wire with a current of 48 A and a second copper wire with a diameter of 2.5 mm suspended 15 cm below it. The relevant equation used is F/l = μ * I1 * I2 / (2 * π * d), where μ is the permeability of free space. The second wire remains suspended, indicating that the current in both wires flows in the same direction and that the magnetic force counteracts the weight of the lower wire. The weight of the lower wire can be determined using its density and dimensions.

PREREQUISITES
  • Understanding of electromagnetic force between parallel conductors
  • Knowledge of the formula for magnetic force per length
  • Familiarity with the properties of copper, including density
  • Basic principles of equilibrium in physics
NEXT STEPS
  • Calculate the weight of the copper wire using its density and dimensions
  • Explore the concept of magnetic permeability and its role in electromagnetic interactions
  • Investigate the stability conditions for parallel current-carrying wires
  • Learn about the applications of Ampère's Law in real-world scenarios
USEFUL FOR

Physics students, electrical engineers, and anyone studying electromagnetic theory or working with current-carrying conductors.

urszula
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Homework Statement



Along horizontal wire carries a current at 48 A. A second wire,made of 2.5 mm diameter copper wire and parallel to the first,is kept in suspension magnetically 15 cm below.Determine the magnitude and direction of the current in the lower wire.Is the lower wire in stable equilibrium?

Homework Equations


F/l= u.I1I2/2(3.14)d

u. -permeability of free space

The Attempt at a Solution



The second wire is not falling down so the current in both wires must be the same direction.I dont't have any idea how to get the force ,because there is no length and mass.
 
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urszula said:
The second wire is not falling down so the current in both wires must be the same direction.I dont't have any idea how to get the force ,because there is no length and mass.

Since the second wire is hovering steadily, the magnetic force from the wire above it must be countering the second wire's weight. You don't need to know the length because your equation gives the magnetic force per length. So just consider, say, the forces on one meter of wire.

What does one meter of this wire weigh? You are given a diameter for it and are told it is made of copper, so you can look up its density. This will allow you to find the mass and weight...
 

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