How Much Current Sustains the Suspended Copper Wire?

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PeachBanana
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Homework Statement



A long horizontal wire carries a current of 48 A. A second wire, made of 3.0 mm diameter copper wire and parallel to the first, is kept in suspension magnetically 15 cm below. Determine the magnitude of the current in the lower wire.

Homework Equations



μI / 2∏r

The Attempt at a Solution



B = (1.256*10^-6)(48 A) / (2∏)(.15 m)^2
B = 4.2639 * 10 ^-4 T

B(2∏r) / μ = I

(4.2639 * 10^-4 T)(2∏)(1.5*10^-3 m)/(1.256 * 10^-6)

I = 3.19 A
 
Attachments
  • Diagram of two parallel horizontal wires; the upper wire is labelled I = 48 A with an arrow pointing right, the lower wire is labelled I = ?, and a vertical double-headed arrow between them is labelled 15 cm.
    Figure1Of1.jpg
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PeachBanana said:
B = (1.256*10^-6)(48 A) / (2∏)(.15 m)^2
B = 4.2639 * 10 ^-4 T


You made an arithmetic mistake .:wink:

B= [4∏*10^-7]*[48]/(2∏*0.15) = 6.4*10^-5 T