Force exerted on U-shaped pipe by steady air-flow help please

Click For Summary
SUMMARY

The discussion centers on calculating the force exerted on a U-shaped pipe by steady airflow, where air enters at a velocity of 10 m/s and exits at the same speed but in the opposite direction. The relevant parameters include an inside diameter of 0.2 m and an air density of 1.23 kg/m³. The user attempted to apply the steady-flow momentum equation, specifically \(\sum\vec{F} = \int\rho\vec{v}(\vec{v}\cdot\vec{n})dA\), but expressed uncertainty regarding the correct application of the equation and the need for the pipe's length. The discussion highlights the importance of understanding the control volume and the forces acting due to velocity changes in the airflow.

PREREQUISITES
  • Understanding of fluid dynamics principles
  • Familiarity with the steady-flow momentum equation
  • Knowledge of air properties, including density
  • Basic concepts of control volumes in fluid mechanics
NEXT STEPS
  • Study the application of the steady-flow momentum equation in fluid dynamics
  • Research the effects of velocity changes on forces in fluid systems
  • Learn about control volume analysis in fluid mechanics
  • Examine examples of force calculations in U-shaped pipe flow scenarios
USEFUL FOR

Students and professionals in fluid dynamics, mechanical engineers, and anyone involved in analyzing airflow in piping systems will benefit from this discussion.

ds7202
Messages
2
Reaction score
0
Force exerted on U-shaped pipe by steady air-flow... help please! :)

Hello! I have attempted this problem, and my result makes sense in my twisted mind. However, it seems like it came too easy!

Homework Statement



Consider a length of pipe bent into a U-shape. The inside diameter of the pipe is 0.2m. Air enters one leg of the pipe at a mean velocity of 10 m/s and exits the other leg at the same magnitude of velocity, but moving in the opposite direction. The pressure of the flow at the inlet and exit is the ambient pressure of the surroundings. Calculate the magnitude and direction of the force exerted on the pipe by the airflow. The air density is 1.23 kg/m^3.

Homework Equations



I attempted this problem using the steady-flow momentum equation, \sum\vec{F} = \int\rho\vec{v}(\vec{v}\cdot\vec{n})dA

The Attempt at a Solution



My attempt at the solution can be viewed here:
http://i.imgur.com/SHItH.jpg


Pleeeeease help! Thanks! :D
 
Physics news on Phys.org


I looked through your calculation, they don't seem wrong, but I didn't study that equation so I don't know if it is correct to use it.

However, I think that a pipe like the one in the problem would move in some way, because it seems very close to the problem of a ball rebounding on a wall: the initial and final condition of the ball are the same, except from the velocity that is the opposite. In these kind of problem, since the velocity varies, you have some forces acting (Newton's second law).
I'd use this way of reasoning - but I'm not sure it is correct. In addition, to perform my calculation I need the length of the pipe, and you did not provided it. So maybe my way is not the correct one. Nevertheless, I think that it must be considered some kind of non-zero force, because the air actually changes its velocity!

Hope you understand (my English is not perfect :D:D:D )
 


I realize what I did wrong. I used the velocity's normal vector instead of the control surface's normal vector, haha
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
Replies
1
Views
3K
  • · Replies 20 ·
Replies
20
Views
11K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
0
Views
2K
Replies
13
Views
4K
Replies
1
Views
2K
Replies
13
Views
4K
Replies
17
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K