Force Experienced on a Curved Geodesic Path

In summary: So, in summary, a person inside a spaceship falling freely on a geodesic path will not experience a force like a person inside a car on Earth experiences during a turn. This is because the geodesic has zero proper acceleration and the tidal forces are only significant for very large ships or near a small black hole. The role of a large ship in experiencing a force due to spacetime curvature is that the larger the volume of space, the greater the effect of geodesic deviation and tidal forces will be. However, the effect is negligible for most situations.
  • #1
rajeshmarndi
319
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Can a person inside a spaceship falling freely on a geodesic path, experience the same just like a person inside a car experience a force on a turn on Earth i.e when the geodesic path is no more straight near a huge planet.

Thanks.
 
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  • #2
No. By definition the geodesic has zero proper acceleration.
 
  • #3
One minor caveat to Orodruin's response - if the spaceship is large enough you will experience tidal forces. This would leave you pressed up against the side of the ship furthest or nearest the mass. Or, more uncomfortably, with one end of your body pressed against one side and the other end against the other.

This will only be a significant effect for a planet-sized ship (that's why we get tides on Earth) or very close to a small black hole.
 
  • #4
Ibix said:
One minor caveat to Orodruin's response - if the spaceship is large enough you will experience tidal forces. This would leave you pressed up against the side of the ship furthest or nearest the mass. Or, more uncomfortably, with one end of your body pressed against one side and the other end against the other.

This will only be a significant effect for a planet-sized ship (that's why we get tides on Earth) or very close to a small black hole.
Little confused, this will only happen near a huge planet if the spaceship is large, because you mention tides on Earth due to moon and close to a black hole.

[edit] If so what is the role of a large ship in which one can experience a force on a turn due to spacetime curvature.
 
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  • #5
rajeshmarndi said:
If so what is the role of a large ship in which one can experience a force on a turn due to spacetime curvature.
In a curved spacetime, nearby geodesics are not quite exactly parallel ("geodesic deviation"), so nearby masses in free fall will want to move apart or be forced together. If the two masses are the opposite ends of some object, that object will experience crushing or stretching forces. The larger the volume of space we're considering, the greater the effect so it will be more pronounced inside a very large ship than a very small one.

Except under very extreme conditions tides are most easily analyzed using Newtonian gravity: use Newton's law to compute the magnitude (slightly different if ##r## is slightly different) and the direction (slightly different for any two points not on the same radius) of the force vectors on two nearby masses in the gravitational field of a planet. The GR model of tidal forces as geodesic deviation is a lot easier to follow after you've worked through the Newtonian equivalent.
 
  • #6
rajeshmarndi said:
Little confused, this will only happen near a huge planet if the spaceship is large, because you mention tides on Earth due to moon and close to a black hole.

[edit] If so what is the role of a large ship in which one can experience a force on a turn due to spacetime curvature.
You always get tidal forces. In Newtonian terms, this is because the parts of the ship nearer the gravitating mass feel a stronger force than those further away. In GR terms, the reasoning is a bit different (geodesic deviation) but the effect is the same, at least qualitatively.

However, the effect is utterly negligible unless you are really, really large (the size of a planet) or in a gravitational field that changes a lot over a short distance (near a small black hole). Whether you are turning or not isn't relevant.
 

1. What is a curved geodesic path?

A curved geodesic path is the shortest path between two points on a curved surface, such as the surface of a planet or a curved space-time. It is similar to a straight line on a flat surface, but takes into account the curvature of the surface.

2. What is the force experienced on a curved geodesic path?

The force experienced on a curved geodesic path is known as the geodesic force. It is the force that keeps an object moving along the shortest path on a curved surface, and is equal to the gravitational force exerted by the curved surface.

3. How is the force experienced on a curved geodesic path calculated?

The force experienced on a curved geodesic path can be calculated using the geodesic equation, which takes into account the curvature of the surface and the velocity of the object. It is a vector equation that describes the acceleration of the object along the path.

4. How does the force experienced on a curved geodesic path affect objects?

The force experienced on a curved geodesic path can affect the motion of objects in different ways, depending on their mass and velocity. For example, objects with larger mass will experience a greater force and therefore a greater acceleration, while objects with smaller mass will experience a smaller force and acceleration.

5. Can the force experienced on a curved geodesic path be countered or manipulated?

Yes, the force experienced on a curved geodesic path can be countered or manipulated by other forces, such as propulsion or gravitational forces from other objects. However, the geodesic force will still be present and will affect the overall motion of the object along the curved path.

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