Force Magnetic Dipole: Electric Current vs Magnetic Pole Model

In summary, there has been a past dispute regarding the validity of the electric current model versus the magnetic pole model for producing a force on a magnetic dipole. However, for elementary particles, it has been settled in favor of the electric current loop model. The difference between these force terms is determined by the vector relation \vec{m} \times (\nabla \times \vec{B}), which only vanishes if the magnetic dipole moment is parallel to the curl of B or if B itself is rotationless. For rotationless magnetic fields, the only solenoidal rotationless fields are constant fields. Therefore, there may be errors when using the second force expression, but the error is usually very small. The term \vec
  • #1
da_willem
599
1
There has been some dispute in the past about the validity of the electric current model of a magnetic dipole producing a force [tex]\nabla (\vec{m}\cdot\vec{B})[/tex] versus the magnetic pole model producing [tex](\vec{m}\cdot \nabla)\vec{B}[/tex] (see e.g. Boyer `87). I think for elementary particles this dispute is now settled in favour of the electric current loop model.

The difference between these two force terms is using some vector relation [tex]\vec{m} \times (\nabla \times \vec{B})[/tex]. But this only vanishes if the magnetic dipole moment is parallel to the curl of B or B itself is rotationless.

But for rotationless magnetic fields, magnetic fields are already solenoidal, what is left? Aren't the only solenoidal rotationless fields constant fields?

So aren't we always making errors when using the second force expression, e.g. in calculating the force on magnetized objects? Or is this error usually very small? Any thoughts?
 
Physics news on Phys.org
  • #2
I guess for example the field of an electromagnet is both solenoidal and irrotational, I had the Helmholtz decomposition wrongly in mind. But still, is the term [tex]\vec{m} \times (\nabla \times \vec{B})[/tex] often/usually negligible or does one generally have to use the first term [tex]\nabla (\vec{m}\cdot\vec{B})[/tex] for a magnetized material?
 
  • #3
For a permanent magnet or an electromagnet, curl B is only non zero on the surface of the magnet, so either force expression should work. There is a delta function term for the energy of two dipoles, which is different for magnetic or electric dipoles. The magnetic form for the delta function is the correct one for elementary particles.
 
  • #4
Thanks for your response, so as long as there are no free currents at the position of the dipole the expressions are the same. The first of the expressions stated includes an interaction associated with an inhomogeneous magnetization whereas the second does not. Wouldn't it imply that there can be only inhomogeneous magnetization when there are currents within the material?
 
  • #5
Each of those expressions refers to the force on a point dipole, or the force on an extended body using the dipole approximation.
The question of spatial dependence of the magnetization M never enters.
If you want the force due to a field B(r) acting on a finite body with magnetization M(r),
you need different equations.
 
  • #6
U're probably right. I'm just looking for an easy way from the expression we have for the force on a single dipole towards the Kelvin force on a magnetized material consisting of many dipoles.
 
  • #7
The easiest way to get the force on a body having permanent magnetization M(r) in an external magnetic field is to introduce (fictitious) magnetic charge.
This is the same as the bound charge in electric polarization P.
The magnetic charge is given by [tex]\rho_m=-\nabla\cdot{\vec M}[/tex]
and surface charge [tex]\sigma_m=M_n[/tex], where [tex]M_n[/tex] is the normal component of M at the surface.
Then [tex]{\vec F}=\int\rho{\vec B}d^3r[/tex].
 
  • #8
pam said:
The easiest way to get the force on a body having permanent magnetization M(r) in an external magnetic field is to introduce (fictitious) magnetic charge.
This is the same as the bound charge in electric polarization P.
The magnetic charge is given by [tex]\rho_m=-\nabla\cdot{\vec M}[/tex]
and surface charge [tex]\sigma_m=M_n[/tex], where [tex]M_n[/tex] is the normal component of M at the surface.
Then [tex]{\vec F}=\int\rho{\vec B}d^3r[/tex].
what happened to the surface charge in the formula for force?

edit:eek:h. I guess its just considered to be bound charge which happens to be at the surface.
 

1. What is a magnetic dipole?

A magnetic dipole is a concept in physics that describes the behavior of a magnetic field created by a pair of poles, similar to how an electric dipole behaves with its positive and negative charges. The term "dipole" refers to the fact that the magnetic field has two opposite poles, one north and one south.

2. How is a magnetic dipole different from an electric dipole?

While both magnetic and electric dipoles have two opposite poles, they differ in the way they are created. An electric dipole is created by separating positive and negative charges, while a magnetic dipole is created by the alignment of tiny magnetic domains in a material or the movement of electric charges.

3. What is the force between two magnetic dipoles?

The force between two magnetic dipoles is determined by the orientation and strength of the dipoles. If the dipoles are aligned in the same direction, they will experience an attractive force, while if they are aligned in opposite directions, they will experience a repulsive force.

4. How does current flow affect a magnetic dipole?

The flow of electric current can create a magnetic dipole in a wire, where one end of the wire becomes the north pole and the other end becomes the south pole. The strength of the magnetic dipole is directly proportional to the amount of current flowing through the wire.

5. Can a magnetic dipole be created without electric current?

Yes, a magnetic dipole can also be created without electric current. Certain materials, such as iron or cobalt, have tiny magnetic domains that can align in the presence of an external magnetic field, creating a magnetic dipole. These materials are known as ferromagnetic materials.

Similar threads

  • Electromagnetism
Replies
23
Views
2K
Replies
4
Views
822
  • Introductory Physics Homework Help
Replies
1
Views
328
Replies
1
Views
346
  • Introductory Physics Homework Help
Replies
3
Views
189
  • Electromagnetism
2
Replies
52
Views
6K
  • Introductory Physics Homework Help
Replies
25
Views
259
  • Electromagnetism
Replies
3
Views
1K
  • Introductory Physics Homework Help
Replies
7
Views
212
  • Electromagnetism
Replies
1
Views
2K
Back
Top