(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 3812.0 kg truck is parked on a 18.1° slope. What is the friction force on the truck?

2. Relevant equations

3. The attempt at a solution

So i set up a triangle with and then used:

weight of truck= (9.8 m/s^2 *3812 Kg) = 37367.6 N

sin(18.1) = (37367.6 N) /(-Ff)

Ff = -120246 N

Could someone explain why this is wrong.. im thinking maybe i set up my triangle incorrectly, but i dont know how else i would draw it.. thanks in advance

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# Force of Friction on object on an incline

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