A 3812.0 kg truck is parked on a 18.1° slope. What is the friction force on the truck?
The Attempt at a Solution
So i set up a triangle with and then used:
weight of truck= (9.8 m/s^2 *3812 Kg) = 37367.6 N
sin(18.1) = (37367.6 N) /(-Ff)
Ff = -120246 N
Could someone explain why this is wrong.. im thinking maybe i set up my triangle incorrectly, but i dont know how else i would draw it.. thanks in advance