Force of Gravity of Al on Mt. Everest

Click For Summary
SUMMARY

The force of gravity acting on Al, who stands at the summit of Mt. Everest (8,848 m elevation) with a mass of 58 kg, can be calculated using the formula F = GMm/r². The Earth’s mass is 5.97e24 kg and its radius is 6.38e6 m. The correct calculation yields a gravitational force of approximately 569.385 N, which is slightly less than the force at sea level due to the increased distance from the Earth's center. The addition of the elevation to the Earth's radius to find the total distance (r) is confirmed as accurate.

PREREQUISITES
  • Understanding of Newton's Law of Universal Gravitation
  • Familiarity with gravitational constant (G = 6.674 × 10⁻¹¹ N(m/kg)²)
  • Basic knowledge of significant figures in scientific calculations
  • Ability to perform calculations involving large numbers and scientific notation
NEXT STEPS
  • Study the implications of gravitational force variations with altitude
  • Learn about the effects of Earth's radius variability on gravitational calculations
  • Explore the concept of weightlessness and how it relates to gravitational force
  • Investigate the application of gravitational force calculations in real-world scenarios
USEFUL FOR

Students in physics, educators teaching gravitational concepts, and anyone interested in the practical applications of gravitational force calculations at varying altitudes.

thelightsare
Messages
9
Reaction score
0

Homework Statement


In this problem find the force of gravity of Al. Al is standing at the top of Mt. Everest at an elevation of 8,848 m. Al has a mass of 58 kg. The Earth has a mass of 5.97e24 and a radius of 6.38e6m. What is the force of gravity acting on Al?


Homework Equations



F = GMm/r^2

The Attempt at a Solution


the dist. used to find F is from Al to the Earth's center ?
so r = 8848+6.38e6 ?
then plug in values

F = G 58(5.97e24)/(8848+6.38e6)^2
F\approx569.385 N?

Is this right? I feel like I'm missing soemthing
 
Physics news on Phys.org
thelightsare said:

Homework Statement


In this problem find the force of gravity of Al. Al is standing at the top of Mt. Everest at an elevation of 8,848 m. Al has a mass of 58 kg. The Earth has a mass of 5.97e24 and a radius of 6.38e6m. What is the force of gravity acting on Al?


Homework Equations



F = GMm/r^2

The Attempt at a Solution


the dist. used to find F is from Al to the Earth's center ?
so r = 8848+6.38e6 ?
then plug in values

F = G 58(5.97e24)/(8848+6.38e6)^2
F\approx569.385 N?

Is this right? I feel like I'm missing soemthing
Hi, welcome to PF! Your equation is correct, but perhaps the values you are using are a bit off, since Al would weigh about 569 N at sea level, (more or less, depending on variabilities in Earth's radius, etc), then he should weigh a wee bit less atop the Mount. But in terms of significant figures, essentially, he weighs pretty much about the same on top as he does at the bottom.
 
Hi! Thanks you for the welcome and your help. And just for reassurance, for r was i right to add the two values together?
 
thelightsare said:
Hi! Thanks you for the welcome and your help. And just for reassurance, for r was i right to add the two values together?
Yes, the distance apart is measured to Earth's center.
 
Thanks so much!
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
Replies
10
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 39 ·
2
Replies
39
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K