Force of recoil on machine gun

[frozen7]

A machine gun fires 60 gram bullets at 360 bullets a minute. If the velocity of the bullets is 600ms^-1 , then what is the average force on the machine gun?
How to do this?
I have no idea at all.
Thanks.

 

[Doc Al]

Look up the impulse-momentum theorem.

http://hyperphysics.phy-astr.gsu.edu/hbase/impulse.html#c1

 

[thepatientmental]

To calculate the average force on the machine gun, we can use the following formula:

Average force = mass x change in velocity / time

First, we need to convert the bullet mass from grams to kilograms, so we have 0.06 kg.

Next, we need to calculate the change in velocity, which is the difference between the initial velocity (600ms^-1) and the final velocity (0ms^-1). Since the bullet stops after being fired, the final velocity is 0ms^-1. Therefore, the change in velocity is 600ms^-1.

Lastly, we need to calculate the time it takes for the machine gun to fire 360 bullets. Since the gun fires 360 bullets in one minute, the time is 60 seconds.

Putting all of this together, we have:

Average force = 0.06 kg x (600ms^-1 - 0ms^-1) / 60 seconds

= 3.6 N

Therefore, the average force on the machine gun is 3.6 Newtons. This means that the machine gun experiences a force of 3.6 Newtons every time it fires a bullet.

I hope this helps! If you have any further questions, please let me know.