Force on an electron in magnetic field:

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SUMMARY

The force on an electron moving with a velocity of 2e6 m/s in the i-direction and -3e6 m/s in the j-direction within a magnetic field of 0.75 T in the i-direction, 0.45 T in the j-direction, and -0.60 T in the k-direction is calculated using the formula F=q(v X B). The resulting force vector is <28.8, 19.2, 50.4> pN after multiplying the cross product by the electron charge of 1.6e-19 C. It is essential to specify both the vector and its magnitude, as the problem does not clarify this requirement.

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krtica
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Q:What is the force on an electron that has a velocity equal to 2e6 m/s i - 3e6 m/s when it is in a region with a magnetic field given by 0.75 T i + 0.45 T j - 0.60 T k?

F=q(v X B)

I took the determinate of the electron's velocity and magnetic field and came up with <1.8e6,1.2e6,3.15e6> then multiplied my answer by 1.6e-19 C. My final answer is <28.8,19.2,50.4>pN.

Did I miscalculate anything?
 
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Assuming the -3e6 m/s speed component is along j, I get same result as you for vXB, but for the force you may want to check the magnitude of you result (I get 0.28 pN for first component). The problem text didn't mention if the result should be specified as a vector or as a magnitude (i.e. |F|), so it would probably be nice touch to include both in your answer.
 
The answer is asked to be given as a vector.
 

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