Force on m by 2m such that m is stationary on M

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SUMMARY

The discussion focuses on a physics problem involving two masses, m1 and M, where m1 is placed on M and connected to another mass m2 via a massless string. The key question is whether a coefficient of static friction, μs, exists that allows m1 to remain stationary on M. The analysis concludes that the static friction must be sufficient to counteract the forces acting on m1 to prevent it from sliding off M. Additionally, when the masses are interchanged, the conditions for static friction remain unchanged, confirming the initial findings.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of static friction and its coefficient (μs)
  • Familiarity with free-body diagrams
  • Basic algebra for solving equations involving forces
NEXT STEPS
  • Study the principles of static friction and its applications in physics problems
  • Learn how to construct and analyze free-body diagrams for multi-mass systems
  • Explore the effects of mass and friction on motion in different scenarios
  • Investigate the role of tension in mass-spring systems and connected masses
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of connected mass systems and the role of friction in motion analysis.

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Homework Statement


A mass m1 is placed upon a second mass M on a horizontal surface. A massless string connects mass m1 to mass m2. If the coefficient of static friction between M and the horizontal surface is μs, answer the following:
a) There is a coefficient of static friction μs between M and m1 such that m1 will remain stationary on M. Prove or disprove.
b) If the masses are now interchanged such that m1 is switched with m2, then the answer to part (a) remains the same. Prove or disprove.

Homework Equations


m1+M=m2
ƩFx=F-T
ƩFy=N-mg


The Attempt at a Solution


N=mg
 
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Please supply the rest of the information. There's obviously some missing.
 
Thats all that my teacher gave me, you can see why I am struggling. Thanks anyway :)
 

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