Force Problem - How do i get the inclination?

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Homework Help Overview

The discussion revolves around a physics problem involving a 10.0 kg object on a horizontal surface with a coefficient of friction of 0.7. The original poster seeks to determine the minimum force required to move the object and the angle at which this force should be applied.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of equations related to friction and force balance. There are mentions of drawing free body diagrams and calculating normal and friction forces. Questions arise about the setup and the implications of applying force at an angle.

Discussion Status

Participants are actively engaging with the problem, with some providing equations and reasoning while others express uncertainty and seek clarification. There is no explicit consensus on the solution, but several lines of reasoning are being explored.

Contextual Notes

Some participants note the importance of considering the angle of the applied force and its effect on the normal force, indicating that assumptions about the problem setup are being questioned.

rose123456789
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A 10.0 kg object is resting on a horizontal surface with coefficient of friction of 0.7. Determine the minimum force F that can move this object. At what inclination should force F be applied? Present your answer in nearest hundredths.

I don't know how where to start?, How do i get the inclination ? thanks for the help
 
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I'm pretty sure there's an equation for this and you already have half of the variables. A quick google search would show you the answer. Try searching for coefficient of friction and in this case it's probably static friction.
 
ok thanks!
 
rose123456789 said:
ok thanks!
Does that mean you found the answer?
Really you should be figuring this out for yourself using free body diagrams and applying the force balance equations. You'll learn more that way than looking the answer up. Besides, it often happens that there is some subtle difference between the problem you are trying to solve and the one you find lying around on the net.
 
oh no, I'm still figuring out the answer
 
haruspex said:
Does that mean you found the answer?
Really you should be figuring this out for yourself using free body diagrams and applying the force balance equations. You'll learn more that way than looking the answer up. Besides, it often happens that there is some subtle difference between the problem you are trying to solve and the one you find lying around on the net.

i'm still figuring out the answer
 
rose123456789 said:
oh no, I'm still figuring out the answer
Ok. Have you drawn yourself a force diagram? What forces do you have, and in what directions do they act?
 
haruspex said:
Ok. Have you drawn yourself a force diagram? What forces do you have, and in what directions do they act?
i calculated that the normal force is 98N and the friction force is 68.6N . and i don't know what is next
 
rose123456789 said:
i calculated that the normal force is 98N and the friction force is 68.6N . and i don't know what is next
just take angle as some 'x' and force as F and write the equations .u wil get as
Fcos x=0.7(w-F sinx)
solving this u wil get the eq. as 10 cos x+7 sin x should me max for the force to be minimum.
and solving x=34.99 degrees
 
  • #10
rohitjinnu16 said:
just take angle as some 'x' and force as F and write the equations .u wil get as
Fcos x=0.7(w-F sinx)
solving this u wil get the eq. as 10 cos x+7 sin x should me max for the force to be minimum.
and solving x=34.99 degrees

how did you get 10 cos x +7 sin x
 
  • #11
rohitjinnu16 said:
just take angle as some 'x' and force as F and write the equations .u wil get as
Fcos x=0.7(w-F sinx)
solving this u wil get the eq. as 10 cos x+7 sin x should me max for the force to be minimum.
and solving x=34.99 degrees
ohhh ok i got it now thanks
 
  • #12
rose123456789 said:
ohhh ok i got it now thanks
kk fn.
 
  • #13
rohitjinnu16 said:
kk fn.

hahahahaha thanks a lot
 
  • #14
rohitjinnu16 said:
kk fn.
ok I'm a bit lost could you explain how did you get 10 cos x +7 sin x
 
  • #15
rose123456789 said:
ok I'm a bit lost could you explain how did you get 10 cos x +7 sin x
F cos x =0.7(w-F sin x)
F cos x/0.7=w-F sin x
F((cos x/0.7)+sin x)=w
F(10 cos x+7 sin x)/7=w
F=(7w)/(10 cos x+7 sinx)
 
  • #16
rose123456789 said:
i calculated that the normal force is 98N and the friction force is 68.6N . and i don't know what is next
You have not allowed for the applied force being at some angle to the horizontal. What will that do to the normal force?
 

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