Force pushing against piston in car engine

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Discussion Overview

The discussion revolves around the force exerted on a piston in a car engine during combustion events. Participants explore the complexities of calculating this force, considering various factors such as engine type, pressure variations, and performance metrics. The conversation includes theoretical aspects and practical implications related to engine mechanics.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Dale inquires about the average force on a piston during combustion, acknowledging variability across different engines.
  • One participant explains that the force on the piston is determined by the piston area and in-cylinder pressure, which can vary significantly based on multiple factors such as engine type and load conditions.
  • Another participant suggests that peak pressures for high-performance gasoline engines can reach around 1100 psi, while top fuel dragsters may experience pressures up to 5000 psi, but emphasizes that these are peak values and not averages.
  • There is a discussion about the complexity of using pressure figures to calculate piston force and engine torque, with a caution that these pressures are only achieved for brief moments.
  • Dale expresses interest in a ballpark figure for the force to compare with other methods of generating similar force.
  • One participant suggests that torque output could be used to estimate the force, while another mentions the need for additional parameters like piston positions and lever arm lengths.
  • A question is raised about the feasibility of achieving similar forces using electromagnetic principles, such as those used in rail guns or coil guns.

Areas of Agreement / Disagreement

Participants generally agree on the complexity of calculating piston force and the variability of in-cylinder pressures. However, there is no consensus on a specific average force value, and multiple competing views on how to approach the calculation remain present.

Contextual Notes

The discussion highlights limitations in deriving average values due to the dependence on specific engine characteristics, operational conditions, and the transient nature of pressure peaks during combustion.

daletaylor
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Hi,

I've done a bit of research to find my answer, but I haven't been able to come up with anything.

Does anyone know what the average amount of force pushing against the piston in a car engine when the explosion occurs? I know it probably differs greatly with the car, but if anyone knows some average force needed for the average car, could you please post it?

Thank you very much,
Dale.
 
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Not to be rude or to brush you off, but if you fully understood the workings of an engine then you'd realize that it's not a very useful question to ask.

I'll try and talk you through the steps here.

Firstly, the force on the piston depends only upon the piston face area (which is fixed for a particular engine, just look at the bore dimension in a data sheet) and the amount of pressure acting thereon. You know that pressure = force / area, so you can work backwards from there.

The pressure side of things is the complicated one. The in-cylinder pressure itself varies drastically on a number of factors. Many of these vary from engine to engine (turbocharging, type of engine (SI/CI), intended use of engine, and so on). When you pin it down to an individual engine, there are still a wealth of factors which affect the pressure. Load and engine speed are probably the two you are concerning yourself with. At low load, or idle, the in-cylinder pressure (and therefore force on the piston) is only sufficient to overcome the parasitic losses in maintaining the engine's state of turning over (friction, pumping power, fans/alternators etc, and other resistive factors). When the demand on the engine is high, for acceleration or developing maximum power, this pressure has to be much higher, and is achieved by burning much more fuel with more air to get more expansion.

I could throw a figure like 2000kPa out there for a 'typical' in cylinder pressure, but it would be completely meaningless with no context.

Would you mind sharing what you're trying to work out so that we can help? Perhaps looking at BMEP would be a much more useful parameter for you.
 
Dale - brewnog already went into detail about how complex the calculation is and how the number doesn't have a direct bearning on output power or loads on the engine.

But for a ballpark, for a very high performance gasoline engine at wide open throttle, the data I've read says the pressure curve may reach a peak of near 1100psi for a naturally aspirated engine. For a forced induction, its going to increase based on the boost, and the same for the addition nitrous oxide. I guess the top fuel dragsters see peak pressures of around 5000psi, but that is a very isolated and extreme example.

You could simply take your average figures and work backwards. So if you had figures of like 10 HP to push the car down the road, engine spinning at 2000 RPM, drivetrain losses of 20%, maybe a cylinder that's 3" in diameter with a 3" stroke and assuming my back-of-napkin-calc is within an order of magnitude of being correct and I come up with 36psi average (with no respect to time). What I don't get is what does that mean? Nothing as far as I can tell, there's far too many other things to consider.
 
Just to reiterate, the pressures we've quoted are peaks, and by no means averages. Using them to calculate a piston force to try to work out engine torque would be completely useless, since these pressures are only attained for a fraction of a second.
 
Hi,

Thanks a lot everyone.

The reason I was asking is just to have a ball park number for the force required to push the piston. I would use this number to compare other methods of creating that same amount of force.

Thanks a lot,
Dale
 
cant you just find that easily from the torque output of the motor?
 
Not real easily, but yes. You need to know the positions of the pistons and the length of the lever arm (where the rod connects to the crankshaft).
 
would it be possible to achieve the same amount of force using an electromagnetic principle?? similar to a rail gun or a coil gun??
 

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