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- Thread starter beamer09
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russ_watters

Mentor

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For the force available, it is just the pressure times the exit area of the nozzle tines the efficiency of the nozzle (try 50%).

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Now I understand your answer. Thank you very much. This will be a very big help.

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How do I find the efficiency of the nozzle? By the effeciency of the nozzle, what do you mean?

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- #9

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Here is a formula that can help you figure out how much pressure you need in order for the rocket to lift of the pad.

F

m = exhaust gas mass flow

V

V

A

P

P

Subtract the F

F

You can then figure out the acceleration using Newton's Second Law which is:

F

or

acceleration = F

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Would a 2 cm nozzle work better?

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In terms of area.

- #14

russ_watters

Mentor

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Mass with water is going to be arbitrary. Not enough and it'll empty quickly, too much and you'll be lifting too much weight. You'll need to do some testing to find the right balance.

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