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Force required to move a object on slope with rolling tyres

  1. Nov 3, 2015 #1
    Consider a object of 5 kilos which is fixed with 4 rolling tyres (like in a trolly) which is in a slanting position of 30 degree angle.

    My question:How to find the force required to move the object upwards the slope along with rolling resistance considered?

    I tried the force using the F push formula for slope & i tried the coeffiecient for friction of tyres as 0.001

    F push= mgsin(theta) + coeff of friction*mgsin(theta)
    F push=5 * 9.8 *sin(30) + 0.001 * 5*9.8 * cos(30)
    F push=25.542 Newton

    Is this correct???

    I researched this problem in google, but since the above problem deals with Rolling friction as its attached with tyres, what is the correct method to find the exact force!!! I s it the correct method to find the object moving up the slope with tyres ?
     
  2. jcsd
  3. Nov 3, 2015 #2

    JBA

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    You equation is correct.
     
  4. Nov 3, 2015 #3
    is it the correct formulae to use it to my problem?
     
  5. Nov 3, 2015 #4

    JBA

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    If the above is a full statement of the problem as presented to you then yes it is; however, I am surprised that you were not given a specific coefficient of rolling resistance as a part of the problem statement.
     
  6. Nov 3, 2015 #5
    as i am using steel surface and rubber tyres, i thought its coefficient is 0.001, but i seriously have a doubt over that coeffienct part..as the slope is steel and the tyre is rubber! is the co efficient i used here is right?
     
  7. Nov 3, 2015 #6

    JBA

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    That is hard to say because the actual rolling resistance of a rubber tyre is a function of the tyre's individual design and even more importantly, its inflation pressure; as a result, to the best of my knowledge there is no one "accepted" value of rolling resistance for inflated rubber tyres.

    As for steel wheels or hard rubber covered steel wheels, I have no background related to those; but, in all of these cases the ultimate rolling resistance is a factor that actually must include the mechanical wheel/axle bearing friction, etc. That is the reason, I am surprised you have not been given a specific value in your problem statement.

    Ultimately, your equation provides for all possibilities, including a value of "0" so for that reason I would find it hard for anyone to question your method of calculation with no factor value given.
     
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