smr101
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I've worked out (i), having problems with (ii). I know that the torque will be force x 0.75 but I haven't had any success in working out the force in the first place.
The discussion revolves around calculating the forces involved in accelerating a wagon on an incline, specifically addressing issues related to torque and the forces required for both horizontal and inclined movement. Participants explore the necessary calculations to determine these forces under varying conditions.
Participants do not reach a consensus on the correct approach to calculating the forces involved, and there are multiple competing views regarding the necessary calculations and their implications.
Some calculations depend on the correct interpretation of angles (degrees vs. radians), and there are unresolved aspects regarding the total torque needed by the motor and how it relates to the forces discussed.
Bystander said:What's the force required to accelerate the wagon if there's no incline?
From the problem statement, "... accelerate the wagon from rest to 2.6 m/s over a distance of 8.2 m at constant acceleration ..."smr101 said:Without an acceleration, I'm not sure.
Bystander said:From the problem statement, "... accelerate the wagon from rest to 2.6 m/s over a distance of 8.2 m at constant acceleration ..."
No. You've got the force to do the acceleration? Can you calculate the force necessary to move the wagon up the incline? Add them.smr101 said:when there is no incline?
Bystander said:No. You've got the force to do the acceleration? Can you calculate the force necessary to move the wagon up the incline? Add them.
Don't just punch numbers into a calculator and blindly accept the number that comes out. What's the sin of 10°?smr101 said:= 1920 x 9.81 x sin10
= -10246.7
Bystander said:Don't just punch numbers into a calculator and blindly accept the number that comes out. What's the sin of 10°?
Bystander said:Better.