Forced response and Laplace transform

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The discussion focuses on solving a differential equation using the Laplace transform technique, specifically for the equation d^2y/dt^2 + 4(dy/dt) + 4y = -7(e^(-3t)). Participants express confusion about applying the Laplace transform correctly, particularly regarding the transformation of derivatives and the right side of the equation. It is emphasized that initial conditions must be included in the transforms, and there is a correction regarding the proper form of the Laplace transforms for the derivatives. The conversation highlights the importance of accurately converting terms and understanding the implications of initial conditions in the context of the Laplace transform. Overall, clarity on these points is essential for progressing with the solution.
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Homework Statement


d'^2 (y)/dt + 4 (dy/dt) + 4y = -7(e^(-3t)). Here I need to forced response of this differential equation using laplace transform technique.


Homework Equations




The Attempt at a Solution


I understand the part of converting each term to each laplace,
d^2y/dt to Y(s)*s^2, dy/dt to Y(s)*s, y(t) to Y(s), where each term is being converted from f(t) to F(s). I really confused on how to proceed with this question form here :cry:
 
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4real4sure said:

Homework Statement


d'^2 (y)/dt + 4 (dy/dt) + 4y = -7(e^(-3t)). Here I need to forced response of this differential equation using laplace transform technique.


Homework Equations




The Attempt at a Solution


I understand the part of converting each term to each laplace,
d^2y/dt to Y(s)*s^2, dy/dt to Y(s)*s, y(t) to Y(s), where each term is being converted from f(t) to F(s). I really confused on how to proceed with this question form here :cry:

Unless you have a couple of 0 initial conditions, you need to put them in the transforms of the derivatives. You also need to transform the right side of the DE. Solve the resulting equation for Y(s) and invert it.
 
I found out by applying laplace to each factor,

s^2y(t)+4sy(t)+4y(t)=-7t(t+3)
s^2y(t)+4sy(t)+4y(t)=-7t(t)-7y(3)
y(t)(s^2+4s+11)=y(3)

But from here, I am confused. Since in the question the value of u(t) was given to be e^-3t. Other wise I would have used laplace transform of u(t) which is 1/s.
Also in the last line, I couldn't factorize the polynomial which is hindering my progress.
Any help would be whole heartedly appreciated.
 
4real4sure said:

Homework Statement


d'^2 (y)/dt + 4 (dy/dt) + 4y = -7(e^(-3t)).

LCKurtz said:
Unless you have a couple of 0 initial conditions, you need to put them in the transforms of the derivatives. You also need to transform the right side of the DE. Solve the resulting equation for Y(s) and invert it.

4real4sure said:
I found out by applying laplace to each factor,

s^2y(t)+4sy(t)+4y(t)=-7t(t+3)

Did you read my reply? Are your initial conditions y(0)=0 and y'(0) = 0 or not? You were using Y(s) for the transform of y(t). You have t's in your transform when they should be s's and y when you should have Y. And where did the t(t+3) on the right side come from? It surely isn't the transform of e^(-3t).
 
4real4sure said:

Homework Statement


d'^2 (y)/dt + 4 (dy/dt) + 4y = -7(e^(-3t)). Here I need to forced response of this differential equation using laplace transform technique.


Homework Equations




The Attempt at a Solution


I understand the part of converting each term to each laplace,
d^2y/dt to Y(s)*s^2, dy/dt to Y(s)*s, y(t) to Y(s), where each term is being converted from f(t) to F(s). I really confused on how to proceed with this question form here :cry:

L[y'(t)](s) ≠ s*Y(s) and L[y"(t)](s) ≠ s^2*Y(s) in general (although for some special conditions on y(.) these are true). Check your sources!

RGV
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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