Forces along non-perpendicular axes

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SUMMARY

The discussion focuses on determining the components of force F2 along non-perpendicular axes u and v using trigonometric calculations. The calculations yield CompF onto U as 6.93 kN and CompF onto V as -2.07 kN, with the angle between F2 and V calculated as 75 degrees. Participants confirm the accuracy of these calculations and express concern over discrepancies in provided answers, suggesting potential errors in the original problem setup. The consensus is that the calculations presented are correct.

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  • Understanding of vector decomposition in physics
  • Knowledge of trigonometric functions, specifically cosine
  • Familiarity with force components and their directions
  • Basic principles of mechanics involving forces
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This discussion is beneficial for undergraduate physics students, mechanical engineers, and anyone involved in analyzing forces in engineering applications.

Imbellis
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Homework Statement
F2 = 8kN; Determine the magnitude of F2 along axis u and axis v.
Relevant Equations
CompF = F*Cos(angle)
question.png
1567124547906.png

Determine Force from F2 along u and v axes.
CompF= F*Cos(angle);
CompF onto U = 8kN*Cos(30) = 6.93kN
Angle between F2 and V: 180-75 = 105; 105-30 = 75 degrees
CompF onto V = 8kN*Cos(75) = 2.07 kN. Since in the -V direction; -2.07kN.

I just would like for somebody to verify these answers. I've already missed credit on the problem (Answers shown below), I'm just clueless how they got those numbers.
1567124522625.png
 
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Your answers are correct. I cannot even figure out what blunder was made in the given answer.
Quite often, it looks like someone modified the numbers in an existing question but failed to update the answer. This one looks weirder.
 
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haruspex said:
Your answers are correct. I cannot even figure out what blunder was made in the given answer.
Quite often, it looks like someone modified the numbers in an existing question but failed to update the answer. This one looks weirder.
Thanks for the confirmation! I just wanted to make sure I wasn't going crazy (I'm an undergrad and would be quite nervous if I made a mistake on a question like this) .
 

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