Forces for bodies connected by a wire on inclined surface

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Homework Help Overview

The discussion revolves around a problem involving forces acting on two bodies connected by a wire on an inclined surface. The participants explore the dynamics of the system, including the effects of tension, friction, and acceleration.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the implications of the wire being inextensible and the necessity for both masses to share the same acceleration. There is also consideration of scenarios where the tension in the wire may be zero. Questions arise regarding the correct setup of equations based on these conditions.

Discussion Status

Some participants have provided guidance on solving the problem symbolically to avoid rounding errors. Others have pointed out the importance of distinguishing between radians and degrees in calculations. The conversation reflects ongoing exploration of different approaches without reaching a consensus.

Contextual Notes

There are mentions of potential rounding errors and the importance of maintaining significant figures in calculations. Additionally, the need for clarity in angle measurement is noted, which may affect the accuracy of the results.

Heexit
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Homework Statement
Two bodies (masses 2 kg and 4 kg) are joined by a wire. The system is laid along a rough inclined plane (the angle of inclination is 30 degrees). For the upper, lighter body, the coefficient of friction is 0.2 and for the lower it is 0.12. what is the thread force after the system is left to itself?
Relevant Equations
F=ma, F=mg, cos, sin,
Hello PhysicsForums!
Here is my attempt at a solution for the problem stated above:
1684412696253.png

Where m1 and m2 are the masses
Where Ff1 and Ff2 are friction for each mass
Where a1 and a2 is the resulting acceleration
Where S is the fore of the wire (threadforce)
Where FN is the normal force

The answear should be 0.91 Newton

Any clues on what I need to change?

Thanks on beforehand for your help!
 
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There are two possibilities that I can see.
  1. The two masses accelerate with the wire under tension (thread force) they must the same acceleration because the wire is assumed inextensible. This means that the velocity of one block does not change relative to the velocity of the other.
  2. The trailing mass is accelerating faster than the leading mass in which case the tension is zero.
You need to determine which possibility is the case here and then write the appropriate equations. Specifically, if (1) is the case, you must use ##a_1=a_2=a## in the equations.
 
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Thanks for your help!

Here is my new solution to the problem (with the correct answear!)
1684415965177.png


Thanks for you help and time!
 
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If you had solved the problem symbolically to find an algebraic expression in the form ##s =\dots~##, you would have avoided round off errors and your answer would have been closer to the given one. Anyway, good job!
 
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Hi @Heexit. I'd like to add a minor point. Writing an angle without units, e.g. ##\sin (30)##, implies the angle is in radians. You should include the degrees symbol if the angle is in degrees, i.e. ##\sin(30º)##.

Not distinguishing between radians and degrees - and not ensuring calculators are in the correct mode (radians-mode or degrees-mode) easily leads to errors.

Also, if you are calculating intermediate values, work and record values to two (or more) extra significant figures in the intemediate steps; this reduces rounding error in the final answer. Or better still, work symbolically till near the end, as suggested by @kuruman.

Edit: typo' corrected.
 
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