- #1

joeG215

- 18

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## Homework Statement

A 1 kg box begins at rest and a hand applies a constant force of 2N along a 2 meter board. The first meter is frictionless, but the second meter has friction that makes the box come to a stop. Time is not give. Coefficient of friction is not given. My question is, is it possible to find acceleration at the 2nd meter and/or the coefficient of friction?

## Homework Equations

$F=ma F(f)=uF(n) u= Coef. of friction

## The Attempt at a Solution

$F= 2N-F(f) =(1kg)(a)

2N-u(9.8N)=1kg(a) I get stuck with two variables.