Forces on a Skydiver during the initial frefall phase of the jump

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Homework Help Overview

The discussion revolves around the forces acting on a skydiver during the initial freefall phase of a jump. Participants are analyzing the effects of gravity and air resistance on the skydiver's acceleration.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of Newton's second law and the forces involved, including gravity and air resistance. There are attempts to set up equations based on the net force acting on the skydiver. Some participants express confusion about how to isolate the mass of the skydiver from the equations provided.

Discussion Status

Some guidance has been offered regarding the formulation of the net force equation, with suggestions to clarify the relationship between the forces acting on the skydiver. Multiple interpretations of the problem setup are being explored, particularly concerning the balance of forces and the implications of acceleration.

Contextual Notes

Participants are working under the constraints of the problem statement, which specifies the forces acting on the skydiver and the acceleration experienced during freefall. There is an emphasis on understanding the dynamics without providing a direct solution.

Balsam
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Homework Statement


A skydiver is jumping out of an airplane. During the first few seconds of one jump, the parachute is unopened, and the magnitude of the air resistance acting on the skydiver is 251N. The acceleration of the skydiver during this time is 5.96 m/s^2 [down]. Calculate the mass of the skydiver.
g=9.8 m/s^2[down]
air resistance=251N[up]
acceleration=5.96m/s^2 [down]

Homework Equations


Fnet=ma
Fg=mg

The Attempt at a Solution


[/B]
I drew a diagram and have plugged in the known variables to each equation. For Fg=mg-- Fg=m(9.8m/s^2[down])

for F=ma-- Fnet=m(5.96 m/s^2[down]).

for Fnet--Fnet= 251N[up] + m(9.8 m/s^2 [down]) x 5.96 m/s^2[down].

I'm stuck here, I don't know how to solve for mass from here.
 
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Balsam said:

Homework Statement


A skydiver is jumping out of an airplane. During the first few seconds of one jump, the parachute is unopened, and the magnitude of the air resistance acting on the skydiver is 251N. The acceleration of the skydiver during this time is 5.96 m/s^2 [down]. Calculate the mass of the skydiver.
g=9.8 m/s^2[down]
air resistance=251N[up]
acceleration=5.96m/s^2 [down]

Homework Equations


Fnet=ma
Fg=mg

The Attempt at a Solution



I drew a diagram and have plugged in the known variables to each equation. For Fg=mg-- Fg=m(9.8m/s^2[down])

for F=ma-- Fnet=m(5.96 m/s^2[down]).[/B]

for Fnet--Fnet= 251N[up] + m(9.8 m/s^2 [down]) x 5.96 m/s^2[down].

I'm stuck here, I don't know how to solve for mass from here.
You should draw a free body diagram of the skydiver and label the forces acting on his body while he's falling. Then, write your equation for Fnet.
 
SteamKing said:
You should draw a free body diagram of the skydiver and label the forces acting on his body while he's falling. Then, write your equation for Fnet.

I did. I assume the only forces are air resistance and gravity and i came to the conclusion that Fg must be greater than 251N (in terms of magnitude) for the person to be falling.
 
Balsam said:
I did. I assume the only forces are air resistance and gravity and i came to the conclusion that Fg must be greater than 251N (in terms of magnitude) for the person to be falling.
The way you wrote the equation for Fnet in the OP is confusing. Try expressing Fnet in terms of the weight of the skydiver and the drag force. Don't include the net acceleration just yet.
 
Fnet=251N-mg=ma
251N=ma+mg
251N=m(a+g)
251N=m(-5.96m/s/s+9.8m/s/s)
251N=m(3.89m/s/s)
251N/(3.89m/s/s)=m
65.36kg=m
 

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