(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Values from previous problem:

Pre-collision: v_{2kg}=6m/s -->, v_{3kg}=3m/s <--

Post-collision: v_{2kg}=2m/s <--, v_{3kg}=5.67m/s -->

Collision time: 0.2 sec

2. Relevant equations

F=mA=m(Δv/Δt)

3. The attempt at a solution

My instinct to solve this was to use the pre-collision values to find out the forces each puck had on each other, because it seems like post-collision values for velocity would be irrelevant because the pucks are no longer having any force on each other. So, I did the following...

Force of 2kg puck on 3kg puck: F=2kg(6m/s / 0.2 sec) = 60N

Force of 3kg puck on 2kg puck: F=3kg(3m/s / 0.2 sec) = 45N

Is this the correct way to approach this problem? Thanks for your help!

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# Homework Help: Forces two objects apply on each other during inelastic collision

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